This year course engages students in becoming skilled readers of prose written in a variety of periods, disciplines, and
rhetorical contexts and in becoming skilled writers who compose for a variety of purposes. More immediately, the course
prepares the students to perform satisfactorily on the A.P. Examination in Language and Composition given in the spring.
Both their writing and their reading should make students aware of the interactions among a writer’s purposes, audience
expectations, and subjects as well as the way generic conventions and the resources of language contribute to effectiveness
in writing. Students will learn and practice the expository, analytical, and argumentative writing that forms the basis of
academic and professional writing; they will learn to read complex texts with understanding and to write prose of
sufficient richness and complexity to communicate effectively with mature readers. Readings will be selected primarily,
but not exclusively, from American writers. Students who enroll in the class will take the AP examination.
Answer:
The answer would be cation
Explanation:
Answer:
Cd is oxidized during the discharge of the battery
Explanation:
Based on the reaction:
2 NiOOH + Cd + 2H₂O → 2Ni(OH)₂ + Cd(OH)₂
And knowing Oxygen and hydrogen never change its charge, we must to find oxidation state of Ni and Cd before and after the reaction:
<em>Ni:</em>
In NiOOH: 2 O = -2*2 = -4 + 1H = +1, = -4 + 1 = -3. And as the molecule is neutral, Ni is 3+
In Ni(OH)₂: OH = -1. As there are 2 OH = -2. That means Ni is +2
The Ni is gaining one electron, that means is been reduced
<em>Cd:</em>
Cd before reaction is as pure solid with oxidation state = 0
Cd after the reaction is as Cd(OH)₂: 2 OH = -2. That means Cd is +2
The Cd is loosing 2 electrons, that means is the species that is oxidized.
