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3 years ago

Write the chemical formula for the ionic compound formed by lithium and fluorine.

Chemistry

1 answer:

aev [14]3 years ago

3 0

Answer:

→ LiF

Explanation:

${ \rm{2Li _{(s)} + F _{2(g)} \dashrightarrow \: 2LiF _{(s)} }}$

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14. In the lab, an experimenter mixes 75.0 g of water (initially at 30oC) with 83.8 g of a solid metal (initially at 600oC). At

avanturin [10]

Answer:

Tungsten is used for this experiment

Explanation:

This is a Thermal - equilibrium situation. we can use the equation.

Loss of Heat of the Metal = Gain of Heat by the Water

$-Q_{m}=+Q_{w}\\$

Q = mΔT $C_{p}$

Q = heat

m = mass

ΔT = T₂ - T₁

T₂ = final temperature

T₁ = Initial temperature

Cp = Specific heat capacity

Metal

m = 83.8 g

T₂ = 50⁰C

T₁ = 600⁰C

Cp = $x$

Water

m = 75 g

T₂ = 50⁰C

T₁ = 30⁰C

Cp = 4.184 j.g⁻¹.⁰c⁻¹

$-Q_{m}=+Q_{w}\\$

⇒ - 83.8 x $x$ x (50 - 600) = 75 x 4.184 x (50 - 30)

⇒ $x$ = $\frac{6276}{46090} = 0.13$ j.g⁻¹.⁰c⁻¹

We know specific heat capacity of Tungsten = 0.134 j.g⁻¹.⁰c⁻¹

So metal Tungsten used in this experiment

8 0

4 years ago

A 96.0 ml volume of 0.25 m hbr is titrated with 0.50 m koh. calculate the ph after addition of 48.0 ml of koh at 25 ∘c.

PilotLPTM [1.2K]

KOH is a strong base and HBr is a strong acid and completely dissociates.
The balanced equation for the reaction is;
KOH + HBr ---> KBr + H₂O
Stoichiometry of acid to base is 1:1
The number of KOH moles reacted - 0.50 M / 1000 mL/L x 48.0 mL = 0.024 mol
number of HBr moles reacted - 0.25 M/ 1000 mL/L x 96.0 mL = 0.024 mol
the number of H⁺ ions are equal to number of OH⁻ ions.
Then the solution is neutral.
pH of neutral solutions at 25 °C is 7.
Therefore pH is 7

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3 years ago

Do you know any of these?

bulgar [2K]

The second one is no

6 0

4 years ago

Read 2 more answers

Calculate the average bond order for a p−o bond (such as the one shown in blue) in a phosphate ion. express your answer numerica

PtichkaEL [24]

Answer: 1/4 is the average bond order for a pâ’o bond (such as the one shown in blue) in a phosphate ion.

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