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Igoryamba
3 years ago
10

Given that Kw for water is 2.4×10−14 M2 at 37 °C, calculate the pH of a neutral aqueous solution at 37 °C, which is the normal h

uman body temperature. pH= Is a pH=7.00 solution acidic, basic, or neutral at 37 °C? neutral basic acidic
Chemistry
1 answer:
Nitella [24]3 years ago
6 0

Answer:

pH = 6.80. The aqueous solution is slightly acid

If pH is 7.00 at 37°C, solution is neutral

Explanation:

2H₂O ⇄  H₃O⁺  + OH⁻     Kw = 2.4×10⁻¹⁴

To determine the pH of a solution, we must consider the [H₃O⁺]

[H₃O⁺] . [OH⁻] = 2.4×10⁻¹⁴

[H₃O⁺] =  [OH⁻]  → √2.4×10⁻¹⁴ =  [H₃O⁺]

1.55×10⁻⁷ = [H₃O⁺]

pH = - log 1.55×10⁻⁷ = 6.80

pH = 7 → neutral

pH < 7 → acid

pH > 7→ basic

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1.How many mL of 0.401 M HI are needed to dissolve 5.97 g of BaCO3?
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Answer:

The answer to your question is:

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1.-

Data

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                     2HI(aq)    +    BaCO3(s)   ⇒   BaI2(aq) + H2O(l) + CO2(g)

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                     5.97 g                -----------------   x

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                    x                     ----------------  0.03 mol of BaCO3

                    x = (0.03 x 2) / 1

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Co⁺² Volume = 167 ml   0.548 M

             CoSO4(aq) + 2NaOH(aq)   ⇒   Co(OH)2(s) + Na2SO4(aq)

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                                0.092 moles      ---------------   x

                                x = (0.092 x 2) /1

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Volume of NaOH = moles / molarity

                             = 0.183 / 0.757

                            = 0.241 l  or 241 ml of NaOH

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