Question

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Answer 1

The maximum value of P = x + 6y subject to the constraints is 9

How to determine the maximum value?

The objective function is given as:

P = x + 6y

The constraints are given as:

2x + 4y ≤ 10

x + 9y ≤ 12

x≥0 y≥0

Rewrite 2x + 4y ≤ 10 and x + 9y ≤ 12 as equations

2x + 4y = 10

x + 9y = 12

Divide 2x + 4y = 10  through by 2

x + 2y = 5

Subtract x + 2y = 5 from x + 9y = 12

x - x + 9y - 2y = 12 - 5

Evaluate the difference

7y = 7

Divide by 7

y = 1

Substitute y = 1 in x + 2y = 5

x + 2(1) = 5

Solve for x

x = 3

So, we have

(x, y) = (3, 1)

Substitute (x, y) = (3, 1) in P = x + 6y

P = 3 + 6 * 1

Evaluate

P = 9

Hence, the maximum value of P = x + 6y subject to the constraints is 9

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