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Anon25 [30]
2 years ago
10

What is the maximum vertical distance between the line y = x 2 and the parabola y = x2 for −1 ≤ x ≤ 2?

Chemistry
1 answer:
Mrac [35]2 years ago
5 0

x2=x+2 at x=−1 and x=2 so we have no need to worry about the end-points

f(x)=x+2−x^2

df/dx=1–2x

and that is zero (indicating a maximum) at x=1/2

So the maximum distance is f(1/2)=2.5–0.25=2.25

learn more about maximum distance between curves here:

brainly.com/question/1603866

#SPJ4

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The energy transferred between samples of matter because of a difference in their temperatures is called a. heat. b. thermochemi
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Answer:

The energy transferred between samples of matter because of a difference in their temperatures is called a. heat.

Explanation:

The first law of thermodynamics establishes that when two bodies with different temperatures are put in contact they will find thermic equilibrium to a final temperature by transferring heat. Thus the correct answer is (a).

Thermochemistry is the study of the transformations of heat energy on the chemical reactions. Chemical kinetics is the study of the rate of chemical reactions. And temperature is the measure of the heat.

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Your answer will be B because sodium and chlorine and both elements and two elements combine to make a compound

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15. Which sample of argon gas has the same number of atoms as a 100.-milliliter sample of helium gas at 1.0 atm and 300. K? A) 5
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The sample of argon gas that has the same number of atoms as a 100 milliliter sample of helium gas at 1.0 atm and 300 is 100. mL at 1.0 atm and 300. K

The correct option is D.

<h3>What is the number of moles of gases in the given samples?</h3>

The number of moles of gases in each of the given samples of gas is found below using the ideal gas equation.

The ideal gas equation is: PV/RT = n

where;

  • P is pressure
  • V is volume
  • n is number of moles of gas
  • T is temperature of gas
  • R is molar gas constant = 0.082 atm.L/mol/K

Moles of gas in the given helium gas sample:

P = 1.0 atm, V = 100 mL or 0.1 L, T = 300 K

n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

For the argon gas sample:

A. n =  1 * 0.05 / 0.082 * 300

n = 0.00203 moles

B. n =  0.5 * 0.05 / 0.082 * 300

n = 0.00102 moles

C. n =  0.5 * 0.1 / 0.082 * 300

n = 0.00203 moles

D. n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

Learn more about ideal gas equation at: brainly.com/question/24236411

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