Answer:
Atom, Sub atomic particle, compound, molecule
Answer:- 71.7 calories
Solution:- it is a unit conversion problem where we need to convert joules into calories.
The unit conversion for these energy units is:
1 calorie = 4.184 joule
The given energy is 300 joules and has to be converted to calories. We will show the set up using dimensional analysis.
= 71.7 calories
So, the energy in calories is 71.7.
Yes it’s for the good of ways
Hello!
So, we are given a ball with a density of 1100 kg/m³, and two liquids: water (1000 kg/m³) and honey (1400 kg/m³). Our goal is to determine if the ball will sink or float in the given liquids.
Let's take two common substances: water and ice. Water has a density of 1000 kg/m³ and ice has a density of about 917 kg/m³. You would notice that the ice is always floating when you put ice and water together. This would occur if you have other substances.
Here's what you should know:
- If the density of an object is greater than the liquid it is in, then that object will sink.
- If the density of an object is less than the liquid it is in, then that object will float.
Since the ball has a density of 1100 kg/m³, and water's density is 1000 kg/m³, then the ball will sink. If the ball is placed in honey, then it will float because the density of honey (1400 kg/m³) is greater than the ball's density.
Therefore, objects with a greater density than the surrounding liquid sink, while objects with a smaller density than the surrounding liquid float, which is the fourth choice.
Answer:
4.4×10² cm³
Explanation:
From the question given above, the following data were obtained:
Diameter (d) = 68.3 mm
Height (h) = 0.120 m
Volume (V) =?
Next, we shall convert the diameter (i.e 68.3 mm) to cm.
This can be obtained as follow:
10 mm = 1 cm
Therefore
68.3 mm = 68.3 mm / 10 mm × 1 cm
68.3 mm = 6.83 cm
Therefore, the diameter 68.3 mm is equivalent 6.83 cm.
Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:
1 m = 100 cm
Therefore,
0.120 m = 0.120 m/ 1 m × 100 cm
0.120 m = 12 cm
Therefore, the height 0.120 m is equivalent 12 cm.
Next, we shall determine the radius of the cylinder. This can be obtained as follow:
Radius (r) is simply half of a diameter i.e
Radius (r) = Diameter (d) /2
r = d/2
Diameter (d) = 6.83 cm
Radius (r) =?
r = d/2
r = 6.83/2
r = 3.415 cm
Finally, we shall determine the volume of the cylinder as follow:
Radius (r) = 3.415 cm
Height (h) = 12 cm
Volume (V) =?
Pi (π) = 3.14
V = πr²h
V = 3.14 × (3.415) ² × 12
V = 440 cm³
V = 4.4×10² cm³
Therefore, the volume of the cylinder is 4.4×10² cm³
