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NeTakaya
3 years ago
14

Which of these figures probably shows a sugar solution containing a small amount of sugar dissolved in water

Chemistry
2 answers:
Vesnalui [34]3 years ago
8 0

Answer:

The correct answer is Sugar has a greater solubility than sand.

Sugar will easily dissolve in water because it has a lower density than sand, therefore it has a greater solubility.

rodikova [14]3 years ago
7 0

Answer:

The correct answer is B.

Explanation:

I had to look at the images to know what options I had. Sugar is soluble in water, so it has a saturation point at which it precipitates as a solid into a solution containing a large amount of sugar. If the amount is small, the sugar dissolves completely and no particles are observed in the solution.

Have a nice day!

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Which compounds are bases in aqueous solution according to brønsted–lowry theory?.
Fittoniya [83]

Ammonia compounds are bases in aqueous solution according to brønsted–lowry theory.

<h3>What are bases?</h3>

A base is a substance that can neutralize the acid by reacting with hydrogen ions.

Ammonia compounds are based on an aqueous solution according to brønsted–lowry theory because the water molecule donates a hydrogen ion to the ammonia, it is the Brønsted-Lowry acid, while the ammonia molecule which accepts the hydrogen ion is the Brønsted-Lowry base. Thus, ammonia acts as a base in both the Arrhenius sense and the Brønsted-Lowry sense.

Hence, ammonia compounds are based on an aqueous solution according to brønsted–lowry theory.

Learn more about the  bases here:

brainly.com/question/16387395

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2 years ago
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Answer:

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Explanation:

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4 0
3 years ago
Help I’ll give 10 points it’s a test
mezya [45]
I believe it’s the last option
6 0
3 years ago
Once the sun's energy reaches the earth's atmosphere through radiation, it is circulated within the atmosphere and oceans throug
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I have 50.00 mL of 0.100 M ethyl amine (C2H5NH2). I gradually add a solution of 0.025 M nitric acid (HNO3) to the ethyl amine so
sergeinik [125]

Answer:

4.00 is the pH of the mixture

Explanation:

The ethyl amine reacts with HNO3 as follows:

C2H5NH2 + HNO3 → C2H5NH3⁺ + NO3⁻

To solve this question we need to find the moles of ethyl amine and the moles of HNO3:

<em>Moles C2H5NH2:</em>

0.0500L * (0.100mol/L) = 0.00500 moles ethyl amine

<em>Moles HNO3:</em>

0.201L * (0.025mol/L) = 0.005025 moles HNO3

That means HNO3 is in excess. The moles in excess are:

0.005025 moles HNO3 - 0.00500 moles ethyl amine =

2.5x10⁻⁵ moles HNO₃

In 50 + 201mL = 251mL = 0.251L:

2.5x10⁻⁵ moles HNO₃ / 0.251L = 9.96x10⁻⁵M = [H+]

As pH = -log [H+]

pH = -log 9.96x10⁻⁵M

pH = 4.00 is the pH of the mixture

6 0
2 years ago
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