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4 years ago

Which of these figures probably shows a sugar solution containing a small amount of sugar dissolved in water

Chemistry

2 answers:

Vesnalui [34]4 years ago

8 0

Answer:

The correct answer is Sugar has a greater solubility than sand.

Sugar will easily dissolve in water because it has a lower density than sand, therefore it has a greater solubility.

rodikova [14]4 years ago

7 0

Answer:

The correct answer is B.

Explanation:

I had to look at the images to know what options I had. Sugar is soluble in water, so it has a saturation point at which it precipitates as a solid into a solution containing a large amount of sugar. If the amount is small, the sugar dissolves completely and no particles are observed in the solution.

Have a nice day!

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What is the molarity of a solution containing 55.8 g of mgcl2 dissolved in 1.00 l of solution?

MakcuM [25]

The answer is 0.59 M.

Molar mass (Mr) of MgCl₂ is the sum of the molar masses of its elements.
So, from the periodic table:
Mr(Mg) = 24.3 g/l
Mr(Cl) = 35.45 g/l
Mr(MgCl₂) = Mr(Mg) + 2Mr(Cl) = 24.3 + 2 · 35.45 = 24.3 + 70.9 = 95.2 g/l

So, 1 mol has 95.2 g/l.

Our solution contains 55.8g in 1 l of solution, which is 55.8 g/l

Now, we need to make a proportion:
1 mole has 95.2 g/l, how much moles will have 55.8 g/l:
1 M : 95.2 g/l = x : 55.8 g/l
x = 1 M · 55.8 g/l ÷ 95.2 g/l ≈ 0.59 M

7 0

3 years ago

Read 2 more answers

A 1.00 L flask is filled with 1.15 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pres

tatiyna

Answer:

The partial pressure of argon in the flask = 71.326 K pa

Explanation:

Volume off the flask = 0.001 $m^{3}$

Mass of the gas = 1.15 gm = 0.00115 kg

Temperature = 25 ° c = 298 K

Gas constant for Argon R = 208.13 $\frac{J}{kg k}$

From ideal gas equation P V = m RT

⇒ P = $\frac{m R T}{V}$

Put all the values in above formula we get

⇒ P = $\frac{0.00115}{0.001}$ × 208.13 × 298

⇒ P = 71.326 K pa

Therefore, the partial pressure of argon in the flask = 71.326 K pa

4 0

3 years ago

How many moles of agcl are contained in 244 ml of 0.135 magcl solution? the density of the solution is 1.22 g/ml?

spin [16.1K]

Since we are only asked for the number of moles, we don't need the information of density. The concentration is expressed in terms of 0.135 M AgCl or 0.135 moles of AgCl per liter solution. The solution is as follows:

Moles AgCl = Molarity * Volume
Moles AgCl = 0.135 mol/L * 244 mL * 1 L/1000 mL
<em>Moles AgCl = 0.03294 mol </em>

3 0

3 years ago

Read 2 more answers

What is the mass of 55mL of glycerin if it’s density is 1.26 g/mL

Serjik [45]

Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

volume = 55 mL

density = 1.26 g/mL

mass = 1.26 × 55 = 69.3 g

We have the final answer as

Hope this helps you

4 0

3 years ago

Whoever gets right I will give you Brainly

Ne4ueva [31]

Answer:

it's either b or d

Explanation:

my guess is b

5 0

3 years ago

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