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pochemuha
3 years ago
14

A scuba diver descends from the surface of the ocean to a coral reef that is about 20 meters below the surface. The pressure on

the diver's body will -----during the descent.
Increase
Decrease
Stay the same
Chemistry
2 answers:
almond37 [142]3 years ago
5 0
I think the answer is increase
Mrac [35]3 years ago
3 0

The correct answer is (A) Increase

Explanation- At the earth's surface, the air pressure exerted on us is a result of the air above us. This air pressure is reduced as we go up in altitudes and the weight of air decreases.

If we go below the water or in a depth, the total pressure being exerted upon us will be the sum of air pressure and the weight of water above us so we can say that the pressure will increase on scuba diver.


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What is the sum of the coefficients in the balanced chemical equation for the combustion of acetone, c3h6o(l), in air?
WITCHER [35]

The sum of the coefficients in the balanced chemical equation for combustion of acetone C3H6O in air  is 11

explanation

<h2>write a balanced chemical equation  for reaction</h2>

that is;  C3H6O + 4O2  → 3CO2 +3H2O

coefficient is the number in front of the chemical formula

the sum of coefficient is therefore= 1 ( in front of C3H6O) + 4 ( in front of O2) + 3 ( in front of CO2) + 3 ( in front of H2O) = 11

6 0
3 years ago
Draw the major organic product for the reaction of 1-phenylpropan-1-one with the provided phosphonium ylide.
prohojiy [21]

Answer:

2-methylene propylbenzene

Explanation:

The Wittig Reaction is a reaction that converts aldehydes and ketones into alkenes through reaction with a phosphorus ylide.

The ketone in this case is 1-phenylpropan-1-one. The provided phosphonium ylide is shown in the image attached. The reaction involves;

i) alkylation  

ii) addition

The product of the major organic product of the reaction is 2-methylene propylbenzene.

4 0
2 years ago
Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI
NeTakaya

Answer :

AgI should precipitate first.

The concentration of Ag^+ when CuI just begins to precipitate is, 6.64\times 10^{-7}M

Percent of Ag^+ remains is, 0.0076 %

Explanation :

K_{sp} for CuI is 1\times 10^{-12}

K_{sp} for AgI is 8.3\times 10^{-17}

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

CuI\rightleftharpoons Cu^++I^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Cu^+][I^-]

1\times 10^{-12}=0.0079\times [I^-]

[I^-]=1.25\times 10^{-10}M

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

AgI\rightleftharpoons Ag^++I^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Ag^+][I^-]

8.3\times 10^{-17}=[Ag^+]\times 1.25\times 10^{-10}M

[Ag^+]=6.64\times 10^{-7}M

Now we have to calculate the percent of Ag^+ remains in solution at this point.

Percent of Ag^+ remains = \frac{6.64\times 10^{-7}}{0.0087}\times 100

Percent of Ag^+ remains = 0.0076 %

8 0
3 years ago
How do we balance chemical equations in order to follow the Law of Conservation of Mass?
Bingel [31]

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6 0
3 years ago
Classify the following materials as solid, liquid, or gas at room temperature: milk, helium, granite, oxygen, steel, and gasolin
Sati [7]
Im not sure but milk is liquid, helium is gas, granite is solid, oxygen is gas, steel is solid, and gasiloine is liquid.
3 0
3 years ago
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