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pochemuha
3 years ago
14

A scuba diver descends from the surface of the ocean to a coral reef that is about 20 meters below the surface. The pressure on

the diver's body will -----during the descent.
Increase
Decrease
Stay the same
Chemistry
2 answers:
almond37 [142]3 years ago
5 0
I think the answer is increase
Mrac [35]3 years ago
3 0

The correct answer is (A) Increase

Explanation- At the earth's surface, the air pressure exerted on us is a result of the air above us. This air pressure is reduced as we go up in altitudes and the weight of air decreases.

If we go below the water or in a depth, the total pressure being exerted upon us will be the sum of air pressure and the weight of water above us so we can say that the pressure will increase on scuba diver.


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What are the amplitude's for both waves A and B?
Bad White [126]

Answer:

Wave A= 20m

Wave B= 30m

Explanation:

The amplitude of a wave is the maximum displacement (or height) from its equillibrum position.

The equilibrium position is at 0 meters for both waves.

Thus, amplitude of wave A= 20m

Amplitude of wave B= 30m

5 0
3 years ago
Which of the following is the largest contributor to the salt ions in the ocean?Select one of the options below as your answer:
IgorLugansk [536]
Option b: chloride.

The table salt is sodium chloride and oceans are rich in it.
7 0
3 years ago
Which phrase describes the decay modes and the half-lives of K-37 and K-42?
andrew11 [14]

Answer: (3) different decay modes and different half-lives

Explanation: Potassium-37 and Potassium-42 have the same number of protons  but different numbers of neutrons i.e. they have same atomic number but different mass number. They are isotopes. Thus K-37 and K-42 have different decay modes

K-37 is positron decay and K-42 is beta decay.

_{19}^{37}{\textrm {Kr}}\rightarrow _{18}^{37}{\textrm {Ar}}+_{+1}^0{\textrm {e}}

_{19}^{42}{\textrm {Kr}}\rightarrow _{20}^{42}{\textrm {Ca}}+_{-1}^0{\textrm {e}}


K-37 has a half life of 1.23 seconds and K-42 has a half life of 12.4 hrs.

Thus they have different decay modes and different half lives.

6 0
3 years ago
Read 2 more answers
Aluminum has a density of 2.70 g/mL. Calculate the mass (in grams) of a piece of aluminum having a volume of 417 mL .
bixtya [17]

Answer:

m = 1125.9 g.

Explanation:

Hey there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the definition of density as mass divided by volume:

d=\frac{m}{V}

Thus, we solve for the mass in the equation to obtain:

m=d*V

Then, we plug in the values to obtain:

m=2.70g/mL*417mL\\\\m=1125.9g

Regards!

5 0
3 years ago
A flask with a volume of 125.0 mL contains air with a density of 1.298 g/L. what is the mass of the air contained in the flask?
horsena [70]
A flask with a volume of 125.0 mL contains air with a density of 1.298 g/L. what is the mass of the air contained in the flask<span>The given are: </span>
<span><span>1.      </span>Mass = ?</span><span><span /></span>
<span><span>2.      </span>Density = 1298 g/L</span>
3.      Volume = 125mL to L
a. 125 ml x 0.001l/1ml = 0.125 L

<span>Formula and derivation: </span><span><span>
1.      </span>density = mass / volume</span> <span><span>
2.      mass </span>= density / volume</span>

<span>Solution for the problem: </span><span><span>

1. mass = </span></span> <span> 1298 g/L / 0.125 L = 10384g
</span>


8 0
3 years ago
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