Electrical energy is converted to waste heat. I’m not sure but this is what I think...
Answer:
197mL of 0,506M HCl
Explanation:
The reaction of HCl + BaCO₃ is:
BaCO₃(s) + 2HCl → BaCl₂(aq) + CO₂ + H₂O.
The moles of BaCO₃ in 9,85 g are:
9,85 g of BaCO₃ ×
= <em>0,0499 moles of BaCO₃</em>
As 1 mol of BaCO₃ reacts with two moles of HCl, for a complete reaction of BaCO₃ to dissolve this compound in water you need:
0,0499 moles of BaCO₃ ×
=<em> 0,0998 moles of HCl</em>
If you have a 0,506M HCl, you need to add:
0,0998 moles of HCl×
= 0,197 L ≡ 197mL
I hope it helps!
Answer:
Reacciones de neutralización
Mg(OH)2
NaHCO3
Bicarbonato de sodio
Cloruro de sodio
Reacciones acido base
HCl + NaOH → NaCl + H2O.
H2SO4 + 2 NaOH → Na2SO4 + H2O.
HCl + NH3 → NH4Cl + H2O.
HCN + NaOH → NaCN + H2O.
Explanation: