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lesya [120]
3 years ago
5

Marissa has a photograph that measures 2 in. by 4 in. She has mounted the picture on a mat so that there is a border that measur

es 1 in. around the picture. The graph shows a representation of the photograph and the mat on the coordinate grid. Marissa has decided to dilate the picture and the mat by a scale factor of 2. Draw the new image for the picture and mat on the coordinate grid.

Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0

Step-by-step explanation:

The initial image of the photo is 2 in by 4 in.  The mat is 4 in by 6 in.

The new image is dilated by a scale of 2.  So we double the dimensions.  The new photo is 4 in by 8 in.  The new mat is 8 in by 12 in.

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insens350 [35]

Answer:

- 4( - 4x - 5) =  - 4 \times  - 4x  - ( - 4) \times ( - 5) \\  = 16x - 20

3 0
2 years ago
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Which of the following constants can be added to x2 + x to form a perfect square trinomial?
solmaris [256]

The constant should be added to form a perfect square trinomial will be 1/4. Then the correct option is D.

<h3>What is a quadratic equation?</h3>

It's a polynomial with a value of zero. There exist polynomials of variable power 2, 1, and 0 terms. A quadratic equation is an equation with one statement in which the degree of the parameter is a maximum of 2.

The expression is x² + x.

Then the constant should be added to form a perfect square trinomial.

Then the constant will be

The square of the half of the coefficient of the variable x is to be added to make a perfect square.

Then the constant will be 1/4.

Then the perfect square will be

\rm \rightarrow x^2 + x + \dfrac{1}{4}\\\\\\\rightarrow x^2 + 2 \times \dfrac{1}{2} x + \left (\dfrac{1}{2} \right )^2\\\\\\\rightarrow \left (x + \dfrac{1}{2} \right)^2

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4 0
2 years ago
What is the surface area of cone below Diameter AB=21 and distance from B to C =36
Vesnalui [34]

Answer:

1533.88261311522

Step-by-step explanation:

<em>Let r be the radius of the (base/circle)</em>

<em>and  L be the slant height of the cone</em>

<em>Formula ………………………………………………………………………………………………………</em>

The surface area of a cone = the (curved/lateral) surface area +  the base

                                             =\pi r^{2}\ \ \ +\ \ \ \pi Lr

=========================================

r=\frac{21}{2} =10.5

L = BC = 36

\text{surface area} =\pi \left( 10.5\right)^{2}  +\pi \times 36\times \left( 10.5\right)

                   =346.360590058275 + 1187.52202305694

                   =1533.88261311522

6 0
2 years ago
What is the following product?
Leona [35]

Answer:

First option: 6y^2sqrt(10) + 12sqrt(5y)

Step-by-step explanation:

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= 6y^2sqrt(10) + 6sqrt(20y)

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3 0
3 years ago
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Georgia [21]

Answer: isosceles

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3 years ago
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