Answer:
89–100
Step-by-step explanation:
Let x represent the grade on the fifth test. The average for 5 tests wants to be between 80 and 90, so we have ...
80 ≤ (78 +62 +91 +80 +x)/5 ≤ 90
Multiplying by 5 gives
400 ≤ 311 +x ≤ 450
Subtracting 311 gives the range for the fifth test grade.
89 ≤ x ≤ 139
Since the maximum available score is 100, the range on the 5th test for an overall B grade is ...
89 ≤ x ≤ 100 . . . . where x is the grade on the 5th test
Answer:
(2,-1.5)
Step-by-step explanation:
6x-4y=18
-x-6y=7
Switch the second equation from standard form to y=mx+b form
-x-6y=7→ -x=7+6y → multiply both sides by -1→ x=-7-6y
Substitute all of the things that equal x into the other equation into x
6x-4y=18→ 6(-7-6y)-4y=18
Simplify
-42-36y-4y=18
Bring - 42 to the other side and add like terms
-42-36y-4y=18→ -40y= 60
Solve for y
y=-1.5
Choose an equation and plug y in it.
-x-6(-1.5)=7
-x+9=7
-x=-2
Multiply both sides by -1
x=2
Answer:
Ok...
Step-by-step explanation:
Well a circle has 360 degrees and this question wants the degree of counter-clockwise.
I think first we subtract 69 from 360, since that is the rotation clockwise, to get the angle of rotation.
360 - 69 is 291 degrees