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lord [1]
3 years ago
7

Practice: Organizing InformationComplete the chart to describe the exponents laws and rules.

Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0
Following the generalized form that you wrote, you know that a negative exponent sends its base to the denominator (or numerator if it's in the denominator already). Or to put it formally as you wrote it, for any nonzero real number a and natural number n, <span>the negative rule of exponents states that </span>a^{-n} =  \frac{1}{a^n}.

So, 6^{-2}= \frac{1}{6^{2}} =  \frac{1}{36}.
You might be interested in
The difference of this equation.
yaroslaw [1]

Answer:

\frac{23}{(y-8)(y+8)}=\frac{23}{y^{2}-64}

Step-by-step explanation:

\frac{3y - 1}{(y-8)(y+8)} -\frac{3}{y+8} = \frac{3y - 1}{(y-8)(y+8)} -\frac{3(y-8)}{(y-8)(y+8)} =\\\\=\frac{3y - 1-3y+24}{(y-8)(y+8)} = \frac{23}{(y-8)(y+8)}=\frac{23}{y^{2}-64}

4 0
3 years ago
Y = -3x+4 and y= 1/2x-3
Papessa [141]

Answer:

{x = 2  , y = -2

Step-by-step explanation:

Solve the following system:

{y = 4 - 3 x | (equation 1)

{y = x/2 - 3 | (equation 2)

Express the system in standard form:

{3 x + y = 4 | (equation 1)

{-x/2 + y = -3 | (equation 2)

Add 1/6 × (equation 1) to equation 2:

{3 x + y = 4 | (equation 1)

{0 x+(7 y)/6 = (-7)/3 | (equation 2)

Multiply equation 2 by 6/7:

{3 x + y = 4 | (equation 1)

{0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{3 x+0 y = 6 | (equation 1)

{0 x+y = -2 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 2 | (equation 1)

{0 x+y = -2 | (equation 2)

Collect results:

Answer:  {x = 2  , y = -2


8 0
3 years ago
Is the line through points p(-8,-4) and Q(5,0) parallel to the line through points R(0,1) and s(-1,-1) ?
vodomira [7]

Answer:

No, they are not parallel

Step-by-step explanation:

7 0
3 years ago
Drag each tile to the correct box.
Tatiana [17]
V= 3.14 r2 h
1. 3.14 x 14 x 14 x 18 = 11083.54
2. 3.14 x 13 x 13 x 17 = 9025.8
3. 3.14 x 15 x 15 x 14 = 9896.02
4 .3.14 x 12 x 12 x 20 = 9047.79
so the order would be the second then the forth then the third then the first
4 0
4 years ago
Read 2 more answers
Janelle graphed a line through (−6, 5) that had a slope of −79. What is the y-coordinate of a point on the line that has an x-co
jeyben [28]

Answer:

The value of the y-coordinate is -706

Step-by-step explanation:

The equation of a straight line is;

y = mx + c

where m is slope and c is t-intercept

Given the slope, we can write the equation as;

y = -79x + c

we need to get c

Just put in the x and y values of the given point

X = -6 and y = 5

5 = -79(-6) + c

5 = 474 + c

c = 5-474 = -469

So the complete equation of the line would

be ;

y = -79x - 469

To get the y-coordinate of the point, just insert the x value into the equation;

y = -79(3) - 469

y = -237 - 469 = -706

4 0
3 years ago
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