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andre [41]
3 years ago
7

1. 3x - 5< 19 3x - 5+<19+ 38 < 3x : x<

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

Love you

Step-by-step explanation:

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What is 28% of $1.00
Mazyrski [523]
28% of 1.00 = 28
To get your answer, multiply .28 * 100.
28% of $1.00 = 28 cents. 
8 0
3 years ago
Read 2 more answers
Mikheal wanted to rewrite the conversion factor "1 yard = 0.914 meters" to create a conversion factor to convert meters to yards
Levart [38]
Divide both 1 yard and 0.914 meters by 1. 1x = 0.914y
Now, since you want 1 meter = "variable"
1 meter times 1 yard divided by 0.914 meters. 
1 meter = 1.094 yards
7 0
3 years ago
The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by: P(x)=-12x^2 +12
Minchanka [31]

Given:

The power generated by an electrical circuit (in watts) as function of its current x (in amperes) is modeled by:

P(x)=-12x^2+120x

To find:

The current that will produce the maximum power.

Solution:

We have,

P(x)=-12x^2+120x

Here, leading coefficient is negative. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

If a parabola is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

In the given function, a=-12 and b=120. So,

-\dfrac{b}{2a}=-\dfrac{120}{2(-12)}

-\dfrac{b}{2a}=-\dfrac{120}{-24}

-\dfrac{b}{2a}=5

Putting x=5 in the given function, we get

P(5)=-12(5)^2+120(5)

P(5)=-12(25)+600

P(5)=-300+600

P(5)=300

Therefore, 5 watt current will produce the maximum power of 300 amperes.

6 0
3 years ago
Mrs. Solar is remodeling a house and is looking for a contractor to do the work. She is getting quotes from 3 different contract
andrezito [222]
#b. The equation y = 50x + 200 represents the total cost that the contractor will charge for x hours of work.
#c. (1, 250); (2, 300); (3, 350)
6 0
3 years ago
4 hours 30 minutes = ? Minutes
tigry1 [53]
The answer is:  " 270 minutes " . 
__________________________________________________________
        →  There are "270 minutes" in "4 hours and 30 minutes" .
__________________________________________________________
Explanation:
__________________________________________________________
Method 1):
__________________________________________________________
  Note:  60 minutes = 1 hour (exactly); 

30 minutes =   ?   hr ? ; 

→  (30 minutes) * (1 hr/ 60 minutes) ;

=
(30/60) hr = (3/6) hr  = (3÷3)/(6÷3) hr ;

=
" \frac{1}{2} hr " ;  

or; write as:  " 0.5 hr " .        
_________________________________________________________

So  "4 hours & 30 minutes" = 4 hours + 0.5 hours = 4.5 hours.

→   4.5 hours  =   ?  minutes ; 

The answer is:  " 270 minutes" .  4.5 hours * \frac{60 min}{1 hr}  ; 

       =  (4.5 * 60) minutes  =  " 270 minutes " .

→  The answer is:  " 270 minutes ".
___________________________________________________________
Method 2)
 
___________________________________________________________

    "4 hours and 30 minutes"  = <u>  ?  </u> minutes " . 
___________________________________________________________

→  " 4 hours   =  <u>  ?  </u> minutes " ; 

→   4 hr . * \frac{60 min}{1 hr}  =  (4 * 60) minutes  =  240 min. ; 

→  There are " 240 minutes in 4 hours" .

→  To find the number of "minutes" in "4 hours and 30 minutes" ;

→  we takes the number of minutes in 4 hours—which is "240 minutes"—and add "30 minutes" to that number; as follows:
   
           →  " 240 minutes + 30 minutes " ; 

to get:   " 270 minutes " . 
_______________________________________________________
 
      →  There are  "270 minutes"  in  "4 hours and 30 minutes" .
_______________________________________________________

The answer is:  
" 270 minutes " . 
_______________________________________________________
4 0
3 years ago
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