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3 years ago

Solve the equation for x: -3(x + 4) + 5x = 24

Mathematics

2 answers:

Makovka662 [10]3 years ago

8 0

Answer:

x = 18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Step-by-step explanation:

Step 1: Define

-3(x + 4) + 5x = 24

Step 2: Solve for x

Distribute -3: -3x - 12 + 5x = 24
Combine like terms: 2x - 12 = 24
Isolate x term: 2x = 36
Isolate x: x = 18

Step 3: Check

Plug in x into the original equation to verify it's a solution.

Substitute in x: -3(18 + 4) + 5(18) = 24
Add: -3(22) + 5(18) = 24
Multiply: -66 + 90 = 24
Add: 24 = 24

Here we see that 24 does indeed equal 24.

∴ x = 18 is the solution to the equation.

mr_godi [17]3 years ago

6 0

<h2>Answer:</h2>

$-3(x + 4) + 5x = 24\\\\-3x - 12 + 5x = 24\\\\2x - 12 = 24\\\\2x = 36\\\\x = 18$

The solution for x in this equation is 18.

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Answer:

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2%7D-1%7D%7B2-5a%7D%20times%20%5Cfrac%7B15a-6%7D%7Ba%5E%7B2%7D%2B5a-6%7D" id=

stepan [7]

$\bf \cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\\\\
-----------------------------\\\\
recall\quad \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
thus\quad a^2-1\iff a^2-1^2\implies (a-1)(a+1)
\\\\\\
now\quad a^2+5a-6\implies (a+6)(a-1)\\\\
-----------------------------\\\\
thus
\\\\\\
\cfrac{a^2-1}{2-5a}\times \cfrac{15-6}{a^2+5a-6}\implies \cfrac{(a-1)(a+1)}{2-5a}\times \cfrac{3(5a-2)}{(a+6)(a-1)}\\\\
-----------------------------\\\\
$

$\bf now\quad 3(5a-2) \iff -3(2-5a)\\\\
-----------------------------\\\\
thus
\\\\\\
\cfrac{\underline{(a-1)}(a+1)}{\underline{2-5a}}\times \cfrac{-3\underline{(2-5a)}}{(a+6)\underline{(a-1)}}\implies \cfrac{-3(a+1)}{a+6}$

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3 years ago

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