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3 years ago

What are the factor pairs of 46 and 76

Mathematics

2 answers:

mel-nik [20]3 years ago

7 0

46
1 x 46
2 x 23

76
1 x 76
2 x 38
4 x 19

Common factors would be 1 and 2.

jolli1 [7]3 years ago

5 0

There are two factor pairs of 46
46= 1 x 46
46= 2 x 23

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write an equation in point-slope form that passes thru the given point and has the given slope? (5,2) m=3

Oduvanchick [21]

Y - y1 = m(x - x1)
slope(m) = 3
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now we sub
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8 0

3 years ago

Read 2 more answers

The terms in a sequence are given by 3 + 2x. what are the first 6 terms in the sequence?

enyata [817]

First 6 terms are 5, 7, 9, 11, 13 and 15

Step-by-step explanation:

Step 1: Given terms in the sequence = 3 + 2x. Find the first 6 terms.

a(1) = 3 + 2 × 1 = 3 + 2 = 5

a(2) = 3 + 2 × 2 = 3 + 4 = 7

a(3) = 3 + 2 × 3 = 3 + 6 = 9

a(4) = 3 + 2 × 4 = 3 + 8 = 11

a(5) = 3 + 2 × 5 = 3 + 10 = 13

a(6) = 3 + 2 × 6 = 3 + 12 = 15

4 0

3 years ago

Estimates show that there are 1.4x10^8 pet fish and 9.4x10^6 pet reptiles in the United States. How many pet fish and reptile pe

azamat

Answer:

There are total number of pet fish and reptile pets are $1.49\times 10^8$ .

Step-by-step explanation:

Number of pet fish are $1.4\times 10^8$ and the number of pet reptiles are $9.4\times 10^6$ .

It is required to find the total number of pet fish and reptile pets in the United States. It can be done by simply adding the above numbers such that total numbers are given by :

$T=1.4\times10^{8}+9.4\times10^{6}\\\\T=149400000\\\\T=1.49\times 10^8$

So, there are total number of pet fish and reptile pets are $1.49\times 10^8$ .

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3 years ago

A selective college would like to have an entering class of 950 students. Because not all students who are offered admission acc

pogonyaev

Answer:

a) The mean is 900 and the standard deviation is 15.

b) 100% probability that at least 800 students accept.

c) 0.05% probability that more than 950 will accept.

d) 94.84% probability that more than 950 will accept

Step-by-step explanation:

We use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .