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kvasek [131]
2 years ago
7

2x + 3 = -x + 12 Solve the equation, explanation is good.

Mathematics
1 answer:
raketka [301]2 years ago
7 0

Answer:

3

Step-by-step explanation:

2x + 3 = -x + 12

subtract 3 from both sides

2x = - x + 9

add x to both sides

3x = 9

divide by 3

x = 3

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What two positive real numbers whose product is 7272 have the smallest possible​ sum?
nadezda [96]
\sqrt{7272} and \sqrt{7272}, or as a rounded decimal 85.28 and 85.28. 

To find the smallest possible sum of roots for any product, the answer is always whatever numbers are closest together. This fact can be derived by the fact that the greatest area we can enclose with a given length is a perfect square. So we can take the square root of 7272 and use that, since they will be exactly the same number. 

If you are looking for whole numbers, you would have to go up or down until you find a factor of 7272 closest to the square root. In this case that would be 72 and 101. 
3 0
3 years ago
PLEASEHELP!
denis-greek [22]
You factor out primes from the root, for example:
root 100
you can get 10 from it, or we'll use 5

100/5=20
20/5=4
root 4= 2
because there are 2 "5" we can bring that out of the root, there are 2 "2" so we bring that out too.
When a number is taking out of a root, the 2 exact same numbers become one. in this case, there are ONE 5 and ONE 2 outside the root. then You multiply 5 and 2 together, and you get 10

6 0
3 years ago
Which list orders the numbers from least to greatest?
s344n2d4d5 [400]
Are u sure you have the answers right? Fix them in a comment and I’ll answer
3 0
2 years ago
Read 2 more answers
Can someone help me with one or two questions??? Thanks :)
shusha [124]

Answer:

yoiu do the firdtone then the poopholestep explanation:

420 69

3 0
3 years ago
Can anyone please help me with this???
ira [324]

Answer:

x=8a

Step-by-step explanation:

(3/a) x - 4 = 20

add 4 to both sides

(3/a) x = 24

Divide by 3/a

x = 24 / (3/a)

Use KCF (keep change flip)

x = (24/1) x (a/3)

x = 24a / 3

simplify

x = 8a

3 0
3 years ago
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