All categories

3 years ago

What is the volume of the prism

Mathematics

1 answer:

Natali [406]3 years ago

3 0

The answer to this question is two hundred and eighty

You might be interested in

What is the equation of the line that passes through the points (-4,8) and (2,-1)

DiKsa [7]

Answer:

y - 8 = (3/2)(x + 4)

Step-by-step explanation:

As we move from (-4, 8) to (2, -1), x increases by 6 (this is the run) and y decreases by 9 (this is the "rise"). Thus, the slope is

m = rise / run = 9/6, or 3/2.

Using the point-slope form of the equation of a straight line, we get:

y - 8 = (3/2)(x + 4)

8 0

3 years ago

Anyone know (Worth lost of points, will mark brainliest!) *I also do not accept links, Sorry!

nadezda [96]

Here ya go! :)
—————-

3 0

3 years ago

At a restaurant you are ordering a sandwich that comes with 2 side dishes. The restaurant has a total of 8 side dishes on the me

katrin [286]

Answer:

16 combos

Step-by-step explanation:

make up your own names for the dishes and then make a chart with all the possible combos that you could have please give brainliest

4 0

3 years ago

Read 2 more answers

Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =

marissa [1.9K]

In Cartesian coordinates, the region is given by $-3\le x\le3$ , $-\sqrt{9-x^2}\le y\le\sqrt{9-x^2}$ , and $-\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}$ . Converting to cylindrical coordinates, using

$\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}$

we get a Jacobian determinant of $r$ , and the region is given in cylindrical coordinates by $0\le\theta\le2\pi$ , $0\le r\le3$ , and $-\sqrt{16-r^2}\le z\le\sqrt{16-r^2}$ .

The volume is then

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3$

6 0

3 years ago

Where does the pythagorean identity sin^2 + cos^2=1 come from? How does it relate to right triangles?

Arada [10]

Consider a right triangle with hypotenuse of 1.
sin x means to divide the side in front of the angle by hypotenuse
cos x means to divide the side beside the angle by hypotenuse
we know that a^2+b^2=c^2 now divide two sides by c^2
$\frac{ a^{2} }{ c^{2} }+ \frac{ b^{2} }{ c^{2} }=1$
c is 1 also a/c means sinx and b/c is cos x so
sin^2(x)+cos^2(x)=1

8 0

4 years ago