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slega [8]
3 years ago
11

What is the volume of the prism

Mathematics
1 answer:
Natali [406]3 years ago
3 0
The answer to this question is two hundred and eighty
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anna is buying a house selling for 185,000. to obtain the mortgage, anna is required to make a 20% down payment. anna obtains a
JulsSmile [24]

Answer:

a. The Amount of the required down payment is $37,000

b. The amount of the mortgage is $148,000

c. The monthly payment for principal and interest is $953.62 per month

Step-by-step explanation:

a) In order to calculate the Amount of the required down payment  we would have to use the following formula:

Amount of down payment = Value of home x Required down payment percentage

= $185,000 x 20%

= $37,000

b)  In order to calculate the Amount of the mortgage we would have to use the following formula:

Amount of the mortgage = Value of home – Down payment

= $185,000 - $37,000

= $148,000

c)  Loan Amount (P) = $148,000

Monthly Interest Rate (n) = 0.5% per month [6.00% / 12 Months]

Number of months (n) = 300 Months [25 Years x 12 Months]

Therefore, the Monthly Loan Payment = [P x {r (1 + r)n} ] / [(1 + r)n – 1]

= [$148,000 x {0.005 x (1 + 0.005)∧300}] / [(1 + 0.005)∧300 – 1]

= [$148,000 x {0.005 x 4.464}] / [4.464 – 1]

= [$148,000 x 0.02232] / 3.464

= $3,303.36 / 3.464

= $953.62 per month

The monthly payment for principal and interest is $953.62 per month

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3 years ago
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Step-by-step explanation:

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Please find the perimeter and area of these shapes
ladessa [460]

Answer:

ABC shaded area = 36\pi - 72   cm²

ABC shaded area perimeter = 6\pi +12\sqrt{2}    cm

ABCD area = \dfrac52 \pi  cm²

ABCD perimeter = 3\pi +2   cm

Step-by-step explanation:

<u>Shape ABC</u>

Assuming you want the area and perimeter of the shaded part of the shape only...

<u>Area</u>

Area of a sector = \dfrac12r^2\theta (where r is the radius and \theta<em> </em>

⇒ area of a sector = \dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi  \ \textsf{cm}^2

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36\pi - 72 cm²

<u>Perimeter</u>

Arc length = r\theta (where r is the radius and \theta<em> </em>

⇒ arc length = 12\times\dfrac12\pi =6\pi  \ \textsf{cm}

Hypotenuse of triangle = \sqrt{a^2+b^2} (where a and b are the legs of the right triangle)

⇒ hypotenuse = \sqrt{12^2+12^2} =12\sqrt{2} cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = 6\pi +12\sqrt{2}  cm

<u>Shape ABCD</u>

<u>Area</u>

Area of a semicircle = \dfrac12 \pi r^2 (where r is the radius)

⇒ area of large semicircle ABC = \dfrac12 \times \pi \times 2^2=2\pi  \ \textsf{cm}^2

⇒ area of small semicircle AD = \dfrac12 \times \pi \times 1^2=\dfrac12\pi  \ \textsf{cm}^2

⇒ area of shape ABCD = \dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2

<u>Perimeter</u>

1/2 circumference = \pi r

⇒ perimeter = 2\pi +2+\pi=3 \pi+2 \ \textsf{cm}

7 0
2 years ago
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