300 minuts
5 hours
1.2 killowatt
6 killowatt hour
6*0.15=0.9
$0.9
Answer:
Before: 0 m/s
After: -4 m/s
Explanation:
Before: Since you and your beau started at rest, your beau initial velocity is 0 m/s.
After: Since we have to conserve momentum,
momentum before push = momentum after push.
The momentum before push = 0 (since you and your beau are at rest)
momentum after push = m₁v₁ + m₂v₂ were m₁ = your mass = 60 kg, v₁ = your velocity after push = 3 m/s, m₂ = beau's mass = 45 kg and v₂ = beau's velocity.
So, m₁v₁ + m₂v₂ = 0
m₁v₁ = -m₂v₂
v₂ = -m₁v₁/m₂ = -60 kg × 3 m/s ÷ 45 kg = -4 m/s
So beau moves with a velocity of 4 m/s in the opposite direction
an independent variable (IV) that you can change. • Typical IV's might be number of fins, length of rocket, type of material, mass of the rocket. • Choose one dependent variable (DV) and make three launches per DV for each IV for a total of. six launches..
Explanation:
Answer:
(a) 
(b) 
Explanation:
Given:
- Limiting tension of snapping of the rope, T= 387 N
- Weight of the object to be lifted,
- ∴mass,
- height of letting down the weight, h = 6.1 m
(a)
Now,
The force to be compensated for being on the verge of snapping:
(T-w) = 62 N
Therefore, we need to produce and acceleration equivalent to the above force.
∵
(b)
From the equation of motion ,we have:
....................(2)
where:
u= initial velocity= 0 (here, starting from rest)
v= final velocity = ?
s= displacement =h =6.1 m
Now, putting the values in eq. (2)
is the velocity with which the body will hit the ground in the given conditions.
