Answer:
3141N or 3.1 ×10³N to 2 significant figures. The can experiences this inward force on its outer surface.
Explanation:
The atmospheric pressure acts on the outer surface of the can. In order to calculate this inward force we need to know the total surface area of the can available to the air outside the can. Since the can is a cylinder with a total surface area given by 2πrh + 2πr² =
A = 2πr(r + h)
Where h = height of the can = 12cm
r = radius of the can = 6.5cm/2 = 3.25cm
r = diameter /2
A = 2π×3.25 ×(3.25 + 12) = 311.4cm² = 311.4 ×10-⁴ = 0.031m²
Atmospheric pressure, P = 101325Pa = 101325 N/m²
F = P × A
F = 101325 ×0.031.
F = 3141N. Or 3.1 ×10³ N.
Since tables display only numerical values, it can be difficult to spot trends by looking at a data table. It is easier to identify trends and relationships in the data by using graphs.
Answer:
The Required pressure for this situation is P= 735000Pa
Explanation:
In Determining the required pressure in this situation we use two equations
First one is
F = mg = (ρhA)g
And Second one is
P = 
= (ρhAg)/A Where P is pressure
We get
P = ρhg
since g = 9.8 m/s and h is given that is 75m and ρ = 
so
P = (9.8 m/s)()(75) we get
P = 735000 Pa
Explanation:
Given that,
The density of water is 1 g/cm³
The density of ethanol is 0.8 g/cm³
We need to find the volume of the ethanol that has the same mass as 100 cm³ of water.
Density=mass/volume
For water,
For ethanol,
Hence, 125 cm³ of ethanol has the same mass as 100 cm³ of water.
Answer:
The velocity of the one thrown up will be the same as the second one
Explanation:
They will fall and hit the ground at the same time although they have the same velocity because object one although has double height it has initial velocity of zero
