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Zielflug [23.3K]
1 year ago
6

√x+3=x-3 a-{6} b-{6,13} c-{1,13} d-{1,6}

Mathematics
1 answer:
ipn [44]1 year ago
6 0

Answer:

d-{1,6}

Step-by-step explanation:

See the picture section.

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Solve the exponential equation<br> help, it's for homework
swat32

Answer: x = 3

Step-by-step explanation:

When the base is the same, the exponents are the same:

3-2x = -x

solve fore x

add 2x to both sides

3-2x = -x

 +2x   +2x

x = 3

6 0
2 years ago
A school's playground, measuring 33 metres, 43 metres, 50 metres and 25 metres, is enclosed by a chain link fence. How many metr
SVETLANKA909090 [29]
Isn’t it just 151 metres?

33+43+50+25=151
4 0
3 years ago
Bentley was playing with 3 old dog toys and 6 new dog toys. If Bentley has 18 old dog toys how many new dog toys does he have?
lawyer [7]

Answer: 36 new dog toys

Step-by-step explanation: With the given information, we can see that Bentley has a total of 18 old dog toys. IF Bentley is playing with a proportional relationship of toys, then all we have to do is multiply 6 by 6. Since 3 times 6 is 18, we have to do 6 times 6 which is 36.

8 0
2 years ago
If you subtract 16 from my number and multiply the difference by -3 the result is -57 what is my number
Sav [38]

Answer:

n=35

Step-by-step explanation:

-3(n-16)= -57

-3n+48= -57

     -48   -48

-3n= -105

/-3       /-3

 n= 35

7 0
3 years ago
Assume that 200 babies are born to 200 couples treated with the XSORT method of gender selection that is claimed to make girls m
JulsSmile [24]

Answer:

a) test statistic = 2.12

b) p-value = 0.017

c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

N = 200

girls (x) = 115 , Boys = 85

p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

<em>aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment </em>.

<u>A) Determine the test statistic </u>

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5)  / \sqrt{0.5*0.5 / 200}  = 2.12

<u>b) determine the p-value</u>

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 )  =  1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0
2 years ago
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