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choli [55]
3 years ago
13

PLEASE HELP I GIVE THANKS

Mathematics
1 answer:
Levart [38]3 years ago
5 0
A=(-6,-2)
B=(6,2)

\sqrt{[(6-(-6)]^2+[(2-(-2)]^2} = \sqrt{12^2+4^2} = \sqrt{16} =4 \sqrt{10}
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Can someone help me please
Trava [24]

Answer:

5n units

Step-by-step explanation:

C=2πr =2·π·2.5

5 0
3 years ago
Drag the correct steps into order to solve the equation -7x + 14 = 56 for x.
Lina20 [59]

Answer:

-7x + 14 = 56

Subtract 14 both sides

-7x + 14 - 14 = 56 - 14

-7x = 42

Divide both sides by -7

(-7x)/(-7) = 42/(-7)

x = -6

3 0
3 years ago
Read 2 more answers
Solve for x<br> -6x+14&lt; -28 or 9x+15≤−12
Free_Kalibri [48]

- 3 \geqslant x > 6

Step-by-step explanation:

....

8 0
3 years ago
Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

7 0
3 years ago
The CEO of a software company is committed to expanding the proportion of highly qualified women in the organization’s staff of
pishuonlain [190]

Answer:

Null Hypothesis, H_0 : p \geq 45%    

Alternate Hypothesis, H_A : p < 45%

Step-by-step explanation:

We are given that the proportion of women in similar sales positions across the country in 2004 is less than 45%.

The collected random sample of size 50 showed that only 18 were women.

<u><em>Let p = proportion of women in similar sales positions across the country in 2004</em></u>

So, Null Hypothesis, H_0 : p \geq 45%    

Alternate Hypothesis, H_A : p < 45%

Here, <u><em>null hypothesis states that</em></u> the proportion of women in similar sales positions across the country in 2004 is more than or equal to 45%.

On the other hand, <u><em>alternate hypothesis states that</em></u> the proportion of women in similar sales positions across the country in 2004 is less than 45%.

The test statistics that would be used here is One-sample z proportion test statistics, i.e;

                        T.S.  =  \frac{\hat p -p}{\sqrt{\frac{\hta p(1-\hat p)}{n} } }  ~ N(0,1)

Hence, the above hypothesis is appropriate for the given situation.

4 0
3 years ago
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