Three squares each have sides of length $6$ units and overlap each other as shown below. The points where the sides cross are mi
1 answer:
The area of the square is 36 square units
<h3>What is a square?</h3>A square is a regular quadrilateral, this explains that it has four equal sides and four equal angles.
It can also be defined as a rectangle with two equal-length adjacent sides.
The properties of a square are:
- All it's Interior angles are equal to 90 degrees
- The four sides of a square are congruent or equal
- Opposite sides of a square are parallel to each other
- Diagonals bisect at 90 degrees
- The two diagonals are equal to each other or congruent
The formula for area of a square is given as;
Area = a ²
Where 'a' is the length of its side
From the information given;
a = 6 units
Now, substitute the values
Area = 6²
Area = 36 units square
Note that this is an overview on the topic as the question seem not to be complete.
The image is attached as part of the complete question
Thus, the area of the square is 36 square units
Learn more about squares here:
#SPJ1
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Answer:
Option D is the right option.
Explanation:
Observe from the graph that the value of X starts at X=0 and the graph is going to the right infinitely.
So the domain of the function should be:
Hope this helps...
Good luck on your assignment..
Since they are both squared.
Evaluating 5^2 and 2^2 and finding the quotient also works.
The third option, "Evaluate 5^2 and 2^2 ...," and the last option, "Rewrite the expression as (5/2)^2 ...," are the correct choices.
Answer:
50% probability that a randomly selected respondent voted for Obama.
Step-by-step explanation:
We have these following probabilities:
60% probability that an Ohio resident does not have a college degree.
If an Ohio resident does not have a college degree, a 52% probability that he voted for Obama.
40% probability that an Ohio resident has a college degree.
If an Ohio resident has a college degree, a 47% probability that he voted for Obama.
What is the probability that a randomly selected respondent voted for Obama?
This is the sum of 52% of 60%(non college degree) and 47% of 40%(college degree).
So
50% probability that a randomly selected respondent voted for Obama.