Volume a sphere: [4/3]π(r^3)
Space between the spheres = Volume of the larger sphere - Volume of the smaller sphere
= [4/3]π (R^3) - [4/3π](r^3) = [4/3]π(R^3 - r^3) = [4/3]π {(5cm)^3 - (4cm)^3} =
= 255.5 cm^3
Answer: 255.5 cm^3
Mohamed decided to track the number of leaves on the tree in his backyard each year. the first year, there were 500 leaves. each year thereafter, the number of leaves was 40% more than the year before. let f(n) be the number of leaves on the tree in Mohamed's backyard in the n^th year since he started tracking it. f is a sequence. what kind of sequence is it?
Number of leaves on the tree in first year = 500
The number of leaves was 40% more than the year before.
So rate of increase is 40/100 = 0.4
We use exponential growth formula,
f(n) = a(1+r)^n
Where a is the initial number, r is the rate of growth, n is the number of years
We know a= 500, r= 0.4
f(n) = 500(1+0.4)^n
f(n) = 500(1.4)^n
Plug in n=1,2,3...
f(1) = 500
f(2) = 500 * 1.4^1
f(3) = 500 * 1.4^2 and so on
From this we can see that the common ratio is 1.4
Hence it is a Geometric sequence.
Answer:
-35
Step-by-step explanation:
7 x -5 = -35
hope this helped!! ^^
Answer:
JL = 78
Step-by-step explanation:
MN is a midsegment. Based on the midsegment theorem,
MN = ½(JL)
MN = 5x - 16
JL = 4x + 34
Plug in the value
5x - 16 = ½(4x + 34)
5x - 16 = ½*4x + ½*34
5x - 16 = 2x + 17
Collect like terms
5x - 2x = 16 + 17
3x = 33
Divide both sides by 3
x = 11
✔️JL = 4x + 34
Plug in the value of x
JL = 4(11) + 34
JL = 44 + 34
JL = 78
In the question it is already given that Eric drove for 439.92 miles on 15.6 gallons. It is required to find the distance traveled on 39.7 gallons of gas. Also we have to find the answer to the nearest hundredth.
Then,
In 15.6 gallons Eric can drive for a distance = 439.92 miles
In 39.7 gallons Eric can drive for a distance = [(439.92/15.6) * 39.7] miles
= 1119.54 miles
So the total distance traveled by Eric is 1120 miles with 39.7 gallons of gas. The answer has been calculated to the nearest hundredth.
