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Nata [24]
3 years ago
10

Help me answer 1 and 2 please

Mathematics
1 answer:
torisob [31]3 years ago
6 0

Answer:

1 is 13/10 i believe and 2 will be 11/12

Step-by-step explanation:

heres my work

1 first find least common factor sense the denominators ar different witch will be ten then then the number you used to multiply the denominator to find 10 you use to multiply the numerator with.

so you left with 6/10 + 7/10 witch equals 13/10

2 do the same in 1 find least common factor witch is 12 and then multiply the number used to get the common factor by the numerator witch leaves the setup as 8/12+3/12 witch equals 11/12

Can i have Brainiest Please.

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Explain how a(b + c) can be rewritten as (b + c)a and as ba + ca.
jenyasd209 [6]

Answer:

#UseDistributiveProperty

Step-by-step explanation:

6 0
3 years ago
A cube made of an unknown material has a height of 9 cm. The mass of this cube is 3.645 grams. What is the density of this cube?
ehidna [41]

Answer:

density =  \frac{mass}{volume}

mass = 3.645 g

volume = 9×9×9

= 729 cm³

density = 3.645/729

= 0.005 gcm^-3

Step-by-step explanation:

the volume is 729 cm³ cause the given height is 9cm and it is a cube. cube has equal sides so their lengths are the same.

volume = length × height × width

8 0
2 years ago
Terry had 400 inches of ribbon before he cut pieces of ribbon that were 8 inches long how many 15 inch pieces can terry cut fro
Nikitich [7]
This could be wrong but the remaining pieces he can cut is 3 because if you divide 400 with 8 , it’s 35 as the answer, so then subtract 35 with 15 till you can subtract 15 from it
4 0
2 years ago
Read 2 more answers
A hula hoop has an circumference 150.72 cm. What is the area of the hula hoop? (round to the nearest hundredth)
Leya [2.2K]

Answer:

Area = 1808.64 cm

Step-by-step explanation:

Circumference of a circle = 2πr

Circumference = 150.72

π = 3.14

r = radius

150.72 = 2 x 3.14 x r

150.72 = 6.28 r

r = 150.72/6.28

r = 24cm

Radius = 24

Area of a circle = πr²

Area = 3.14 x 24²

Area = 3.14 x 576

Area =1808.64 cm

6 0
2 years ago
Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that
aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

A\cap B={HH}

B\cap C={HH}

A\cap C={HH}

P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

P(A)=\frac{2}{4}=\frac{1}{2}

Number of favorable cases to event B=2

Number of favorable cases to event C=2

P(B)=\frac{2}{4}=\frac{1}{2}

P(C)=\frac{2}{4}=\frac{1}{2}

If the two events A and B are independent then

P(A)\cdot P(B)=P(A\cap B)

P(A\cap)=\frac{1}{4}

P(B\cap C)=\frac{1}{4}

P(A\cap C)=\frac{1}{4}

P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}

P(B)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(C)=\frac{1}{4}

P(A)\cdot P(B)=P(A\cap B)

Therefore, A and B are independent

P(B)\cdot P(C)=P(B\cap C)

Therefore, B and C are independent

P(A\cap C)=P(A)\cdot P(C)

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0
3 years ago
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