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DiKsa [7]
3 years ago
13

What algebraic property does this statement show? If 7 = x, then x = 7.

Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0
Symmetric Property
Hope This Helps and God Bless!
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Can some help with this question
marissa [1.9K]

Answer:

y + 1 = 3(x - 1)

Step-by-step explanation:

The given point is (1,-1) meaning that x1 = 1 and y1 = -1

The slope of this line is m = 3 because we go up 3 and over to the right 1 (eg: go from the point (1,-1) to (2,2) to see this in action)

Plug these three pieces of info into the point slope formula below

y - y1 = m(x - x1)

y - (-1) = 3(x - 1)

y + 1 = 3(x - 1)

6 0
3 years ago
Read 2 more answers
Complete the steps to factor 2x2 + x + 5x + 15 by grouping.
arlik [135]

Answer:

19+6x

Step-by-step explanation:

2×2+x+5x+15

4+6x+15

19+6x

7 0
3 years ago
Plz help!:&gt; also your so awesome, and I hope you have an amazing day!<br><br>​
statuscvo [17]
It’s graph 2 because it is. There is a pause for the taking the bath and then the emptiest mhm so it can’t be graph 3
6 0
2 years ago
A certain kind of bacteria multiplies at a rate of 150 percent per hour. When a person’s blood has 45,000,000 of these bacteria,
DIA [1.3K]
Initial number of Bacteria = Ao = 100
Number of Bacteria which make the person ill = A = 45,000,000

Growth rate = r = 150% = 1.50 

The equation model for this situation is:

A= A_{o}(1+r)^{t}

Using the values in above equation, we can write:

45000000=100(1+1.5)^{t}  \\  \\ &#10;450000=(2.5)^{t} \\  \\ &#10;log(450000)=log((2.5)^{t})  \\  \\ &#10;log(450000)=t*log(2.5) \\  \\ &#10;t= \frac{log(450000)}{log(2.5)} \\  \\ &#10;t=14.21

This means, the person will fall sick after about 14 hours.
8 0
3 years ago
Read 2 more answers
If tan tetha =8/15,find the value of sin tetha+cos tetha all divided by cos tetha (1-cos tetha)​
Dahasolnce [82]

Answer:  195.5 or 12 7/32

Step-by-step explanation:

There is no letter tetha in the table so I use α instead. However it is not sence to final result.

The expression is:

(sinα+cosα)/(cosα*(1-cosα))

Lets divide the nominator and denominator by cosα

(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=

=(8/15+1)/(1-cosα)= 23/(15*(1-cosα))    (1)

As known cos²α=1-sin²α   (divide by cos²α both sides of equation)

cos²a/cos²α=1/cos²α-sin²α/cos²α

1=1/cos²α-tg²α

1/cos²α=1+tg²α

cos²α=1/(1+tg²α)

cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=

=+-sqrt(225/289)=+-15/17   (2)

Substitute in (1) cosα  by (2):

1st use cosα=15/17

1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5

2-nd use cosα=-15/17

2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32

7 0
3 years ago
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