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BaLLatris [955]
2 years ago
8

Jordan is preparing serving of baby carrots. He has 96 baby carrots, each serving is 12 carats, how many shearings can Jordan pr

epared will Jordan have any cares left over while why not.
Mathematics
1 answer:
lesantik [10]2 years ago
5 0

Answer: See explanation

Step-by-step explanation:

Since we given the information that Jordan is preparing serving of baby carrots and that he has 96 baby carrots, while each serving is 12 carats.

The number of shearings that Jordan can prepare will be:

= 96 / 12

= 8

From the above calculation, there won't be any carrots left since we do not have a remainder.

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Step-by-step explanation:

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Calcular los perimetros de las siguientes figuras porfa ayúdenme ya​
Basile [38]

Answer:

solo suma todos los valores x+4(3)+(x+x)

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7 0
3 years ago
Given: Q=7m+3n,R=11-2m,s=n+5,and T =-m-3n+8 simplify Q-[R+S]-T
Gnesinka [82]

Answer:

Simplify

Q-[R+S]-T

The answer is:

10m+5n-24

Step-by-step explanation:

We have the expressions:

Q=7m+3n\\R=11-2m\\S=n+5\\T=-m-3n+8

Now, we need simplify:

Q-[R+S]-T

We need to replace each term by the expressions:

7m+3n-[(11-2m)+(n+5)]-(-m-3n+8)

We need to remember the rule of signs:

-/-=+

-/+=-

+/+=+

With this in mind we solve the parentheses:

7m+3n-[(11-2m)+(n+5)]-(-m-3n+8)

7m+3n-[11-2m+n+5]+m+3n-8

7m+3n-11+2m-n-5+m+3n-8

let's group common terms

7m+3n-11+2m-n-5+m+3n-8\\7m+2m+m+3n-n+3n-11-5-8

We must add and subtract common terms:

7m+2m+m+3n-n+3n-11-5-8\\10m+5n-24

The answer is:

10m+5n-24

7 0
3 years ago
Suppose the probability that a randomly selected​ man, aged 55​ - 59, will die of cancer during the course of the year is StartF
sveticcg [70]

Answer:

The probability that a man in this age category does NOT die of cancer during the course of the​ year is 0.997.

Step-by-step explanation:

Suppose the probability of an event occurring is P_{i}.

The probability of the given event not taking place is known as the complement of that event.

The probability of the complement of the given event will be,

1 - P_{i}

In this case an events <em>X</em> is defined as a man, aged 55​ - 59, will die of cancer during the course of the year.

The probability of the random variable <em>X</em> is:

P (X) = \frac{300}{100000}=0.003

Then the event of a man in this age category not dying of cancer during the course of the​ year will be complement of event <em>X, </em>denoted by<em> X</em>'.

The probability of the complement of event <em>X</em> will be:

P(X')=1-P(X)

          =1-0.003\\=0.997

Thus, the probability that a man in this age category does NOT die of cancer during the course of the​ year is 0.997.

7 0
2 years ago
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