Answer:
The new temperature is 1596 C.
Explanation:
Charles's Law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.
Statistically, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio that exists between the volume and the temperature will always have the same value:
Being an initial state 1 and a final state 2, it is fulfilled:
In this case:
- V1= 25 L
- T1= 350 C= 623 K (being 0 C= 273 K)
- V2= 75 L
- T2= ?
Replacing:
Solving:
T2= 1869 K= 1596 C
<u><em>The new temperature is 1596 C.</em></u>
The answer is it contains the electrodes. Without the salt scaffold, the arrangement in the anode compartment would turn out to be decidedly charged and the arrangement in the cathode compartment would turn out to be contrarily charged, on account of the charge lopsidedness, the terminal response would rapidly stop.
It keeps up the stream of electrons from the oxidation half-cell to a decrease half cell, this finishes the circuit.
Answer:
In the chemical bonds.
Explanation:
There are different types of chemical bonds, some store a TON of energy while others do not store as much. You can think of it like this: for bonds with low energy, it takes a LOT of force to pull them apart, meaning they are strong bonds. However, this way, you have to put energy into them to break the bonds and form a chemical reaction. This is an endothermic reaction, a reaction that absorbs heat from its surroundings.
Instead, bonds in exothermic reactions are BEGGING to form a more stable bond, and hence store a lot of potential energy. Due to the difficulty of maintaining these bonds, there is a lot of energy put into them. If you break them, however, (exothermic reaction) the energy is released, and hence the exothermic reaction happens.
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Hello there.
The answer here is true. Cold objects melt faster in hot water than cold water.
<u><em>Answer: The answer is False</em></u>
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