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frez [133]
3 years ago
10

Why is the separation of mixtures into pure or relatively pure substances so important when performing a chemical analysis?

Chemistry
1 answer:
N76 [4]3 years ago
3 0

Answer:

It is important to separate mixture into pure or relatively pure substances when performing a chemical analysis SO AS TO KNOW THE PROPERTIES COMING FROM EACH PART MIXTURE WHICH MAY INTERFERE WITH THE SEPARATION.

Explanation:

In chemistry, Mixture is the combination of two or more substances which are not combine chemically.

Mixture contain different substances with different physical and chemical properties.

It is important to purify the substances in a mixture so as to identify what properties are coming from each mixture and also some part of the mixture can interfere with the properties of other mixture present for skewing analysis.

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WILL GIVE BRAINLIEST helpp asapp
kati45 [8]
The answers are:

1. D
2. B if it is a check all that are true it is b & d
6 0
2 years ago
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A fluid occupying has a mass of 4mg. Calculate its density and specific volume in SI, EE, and BG units.
kondaur [170]

The question is incomplete, complete question is:

A fluid occupying 3.2 m^3 of volume has a mass of 4 Mg. Calculate its density and specific volume in SI, EE, and BG units.

Explanation:

1) Mass of liquid = m = 4 Mg = 4 × 1,000 kg = 4,000 kg

(1 Mg = 1000 kg)

Volume of the fluid = V = 3.2 m^3

Density of the fluid = D

D=\frac{m}{V}=\frac{4,000 kg}{3.2 m^3}=1,250 kg/m^3

Specific volume is the reciprocal of the density :

V_{specific}=\frac{1}{Density}

Specific volume of the fluid = S_v

S_v=\frac{1}{D}=\frac{1}{1,250 kg/m^3}=0.0008 m^3/kg

2)

Density of the fluid in English Engineering units  = D (lb/ft^3)

1 kg = 2.20462 lb

1 m = 3.280 ft

D=\frac[1,250\times 2.20462 lb}{(3.280 ft)^3=78.95 lb/ft^3

Specific volume of the fluid :

=\frac{1}{78.95 lb/ft^3}=0.0127 ft^3/lb

3)

Density of the fluid in British Gravitational System units  = D (slug/ft^3)

1 kg = 0.06852 slug

1 m = 3.280 ft

D=\frac[1,250\times 0.0685218 slug}{(3.280 ft)^3=2.43 slug/ft^3

Specific volume of the fluid :

=\frac{1}{2.43 slug/ft^3}=0.412 ft^3/slug

7 0
3 years ago
Which of the following situations most likely indicates the lowest relative humidity? situation A situation B situation C situat
statuscvo [17]

Answer:

Situation B indicates the significant depression of temperature in the wet bulb thermometer.

Answer Statement: B

Explanation:

Temperature Depression & Relative Humidity

As we can see that there are four cases to study the affect of relative humidity  on the temperature measured by thermometers, set up in different situations i.e., one is dry and the other one is dry.

As situation B describes the most admissible temperature drop in the wet bulb thermometer with a relative humidity of approximately 17% i.e., this can be the appropriate to reflect the lowest relative humidity with a fact that the relative humidity reduces with a larger count of temperature depression. Whereas, the relative humidity for other situations are resulting much higher.

5 0
3 years ago
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which of the following statements correctly describes the relative masses of the particles in atoms ​
zysi [14]

Answer:

protons and neutrons

Explanation:

protons and neutrons is equal to mass number

6 0
2 years ago
On the cooling curve below, between points Dand Ethe substance is changing from
Irina-Kira [14]
Gas to solid ( a ) is correct i think
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