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2 years ago

24 quarts =________gallons

Mathematics

1 answer:

kondaur [170]2 years ago

5 0

I think it’s 6 gallons

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What is 2226 ÷ 53?????

olga_2 [115]

42!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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3 years ago

Read 2 more answers

FIND THE VOLUME OF A CONE 0F DIAMETER 14M AND HEIGHT 21CM. (TAKE = 3 )

Ksenya-84 [330]

Answer:

343π

Step-by-step explanation:

To find the volume of a cone, we have to use this formula

$\frac{1}{3}$ × π × r² × h

Where 'r' is the radius and 'h' is the height

Let's start putting in the value's

We have diameter but in the formula we need the radius so we half the diameter to get the radius so 14 ÷ 2 = 7

$\frac{1}{3}$ × π × r² × h

$\frac{1}{3}$ × π × 7² × 21

→ Simplify the expression

$\frac{1}{3}$ × π × 49 × 21

→ Simplify it further

343π

6 0

2 years ago

Seven less than a number, divided by 5, is -2

ycow [4]

Answer:

$\frac{x - 7}{5} = 2 \\cross \: multiply \\ x - 7 = 10 \\ x = 17$

hope this helps you

4 0

3 years ago

For the right triangle find the missing length Round your answer<br> the nearest teren

Talja [164]

Answer:

hello! i can answer in the comments if you tell me what the lengs are and where they are located! i cannot see the picture due to my school computer blocking images on the site so that's why i need the explanation. thanks :>

5 0

2 years ago

Find lim ?x approaches 0 f(x+?x)-f(x)/?x where f(x) = 4x-3

Whitepunk [10]

If $f(x)=4x-3$ :

$\displaystyle\lim_{\Delta x\to0}\frac{(4(x+\Delta x)-3)-(4x-3)}{\Delta x}=\lim_{\Delta x\to0}\frac{4\Delta x}{\Delta x}=4$

If $f(x)=4x^{-3}$ :

$\displaystyle\lim_{\Delta x\to0}\frac{\frac4{(x+\Delta x)^3}-\frac4{x^3}}{\Delta x}=\lim_{\Delta x\to0}\frac{\frac{4x^3-4(x+\Delta x)^3}{x^3(x+\Delta x)^3}}{\Delta x}$

$\displaystyle=\lim_{\Delta x\to0}\frac{4x^3-4(x^3+3x^2\Delta x+3x(\Delta x)^2+(\Delta x)^3)}{x^3\Delta x(x+\Delta x)^3}$

$\displaystyle=\lim_{\Delta x\to0}\frac{-12x^2\Delta x-12x(\Delta x)^2-4(\Delta x)^3}{x^3\Delta x(x+\Delta x)^3}=-\frac{12}{x^4}$

7 0

3 years ago