All categories

3 years ago

Slove the equation ×+20=29

Mathematics

1 answer:

photoshop1234 [79]3 years ago

8 0

Answer: x = 9

Step-by-step explanation:

x + 20 = 29

x = 9

9 + 20 = 29

You might be interested in

TRUE OR FALSE: FOR ANY FUNCTION, X=F^-1(Y), THEN Y=F(X). PLEASE EXPLAIN

Vesnalui [34]

Answer:

True.

Step-by-step explanation:

For example let f(x) = 3x + 1 then f-1(x) is found as follows

Let f(x) = y = 3x + 1 then

3x = y - 1

x = (y-1) / 3

x = f-1(x) = (x - 1)/3.

So:

Replacing the x in y by (x - 1)/3 :-

x = f(-1)(y) = ( (3x + 1) - 1) / 3

= 3x / 3

= x.

So y = f(x).

7 0

3 years ago

The Kuroshio Sea tank is 27m long, 35m wide and 10m deep. What is the volume of the tank? Show your

umka21 [38]

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

Step-by-step explanation:

The given is,

Kuroshio Sea tank is 27m long, 35m wide and 10m deep.

Step:1

Sea tank looks like a rectangular prism,

Formula to calculate the volume of rectangular prism,

$Volume, V =whl$ .............................(1)

Where, w - Width of the rectangular prism

h - Height or depth of the rectangular prism

l - Length of the rectangular prism

From given,

w = 35 meters

l = 27 meters

h = 10 meters

Equation (1) becomes,

$V = (35)(10)(27)$

$= (945)(10)$

$=9450$

Volume of the sea tank, V = 9450 Cubic meters

Result:

The volume of Kuroshio Sea rank is 9450 cubic meters, if the sea tank is 27m long, 35m wide and 10m deep.

3 0

3 years ago

Find the average value of f over region

SVETLANKA909090 [29]

$D$ is a right triangle with base length 1 and height 8, so the area of $D$ is $\dfrac12(1)(8)=4$ .

The average value of $f(x,y)$ over $D$ is given by the ratio

$\dfrac{\displaystyle\iint_Df(x,y)\,\mathrm dA}{\displaystyle\iint_D\mathrm dA}$

The denominator is just the area of $D$ , which we already know. The average value is then simplified to

$\displaystyle\frac74\iint_Dxy\,\mathrm dA$

In the $x,y$ -plane, we can describe the region $D$ as all points $(x,y)$ that lie between the lines $y=0$ and $y=8x$ (the lines which coincide with the triangle's base and hypotenuse, respectively), taking $0\le x\le1$ . So, the integral is given by, and evaluates to,

$\displaystyle\frac74\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=\frac78\int_{x=0}^{x=1}xy^2\bigg|_{y=0}^{y=8x}\,\mathrm dx$
$=\displaystyle56\int_{x=0}^{x=1}x^3\,\mathrm dx$
$=14x^4\bigg|_{x=0}^{x=1}$
$=14$

3 0

3 years ago

In year 13, the scientist will put tree wrap around tree 1 to protect it from the winter snow. The height of the tree wrap needs

Dominik [7]

Answer:

22 feet²

Step-by-step explanation:

We are given:

height of tree h = 45 inches

Circumference= πd × inches

But d = 22.2inches

Therefore area will be

Area = 22.2π × 45 inches²

Area = 3137 inches²

Let's convert from inches² to feet², we have:

1 foot = 12 inches.

Therefore,

1 square foot = 1foot × 1foot = 12inches×12inches

= 3137inches² / 144 inches²

= 22feet²

Note: I attached missing data which states that diameter at year 13 is 22.2inches

6 0

2 years ago

Read 2 more answers

Find the value of x in the isosceles triangle shown below

levacccp [35]

Answer:

x=10

Step-by-step explanation:

$\frac{x}{2}=\sqrt{13^2-12^2} \\x=2\sqrt{169-144} \\x=2\sqrt{25} \\x=2 \times 5=10$

4 0

3 years ago