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Nezavi [6.7K]
2 years ago
12

5.3: Solutions on a Number Line

Mathematics
1 answer:
andrew11 [14]2 years ago
5 0

Answer:

idfk

Step-by-step explanation:

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What is the answer for this equation or problem? y+6=52 and what does y equal.
Cloud [144]

Answer: y=46

Step-by-step explanation:

Subtract 6 from either side to ensure that the y is alone. This then equals y=52-6.

52-6= 46

So therefore, y=46

4 0
3 years ago
Read 2 more answers
Write an equation of the line with the given characteristics (show all work)
Sedbober [7]

Answer:

1. y = - 4 x + 5

2.  x = -8

Step-by-step explanation:

1.  (-1,9) (1,1)

y = mx + b

m = (y-y') / (x-x') = (1-9) / (1-(-1)) = -8 / 2 = - 4

b = y - mx = 9 - (-4) x (-1) = 5

equation: y = - 4 x + 5

check: (1,1)   y=1 = (-4) x 1 + 5 = 1

2. Vertical line through (-8,6) is a line perpendicular to x axis

    x = -8

4 0
3 years ago
Determine the y-intercept and slope and then write the equation for this table.*​
Novosadov [1.4K]

Answer:

The y-intercept is 15 and the slope is 5.5

y=5.5x+15

Step-by-step explanation:

4 0
3 years ago
A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data
Rasek [7]

Answer: a. 1.981 < μ < 2.18

              b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

\overline{x}=\frac{\Sigma x}{n}

\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}

\overline{x}= 2.08

Now, we estimate standard deviation:

s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }

s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }

s = 0.1564

For t-score, we need to determine degree of freedom and \frac{\alpha}{2}:

df = 12 - 1

df = 11

\alpha = 1 - 0.95

α = 0.05

\frac{\alpha}{2}= 0.025

Then, t-score is

t_{11,0.025} = 2.201

The interval will be

\overline{x} ± t.\frac{s}{\sqrt{n} }

2.08 ± 2.201\frac{0.1564}{\sqrt{12} }

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

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3 years ago
After traveling 345 miles, the
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<h2>GOOD LUCK CHUCK :)))))))))</h2>
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