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2 years ago

What is the equilibrium constant for the reaction

Chemistry

1 answer:

yan [13]2 years ago

7 0

Answer:

B.) $K_{eq} = \frac{[SO_3][NO]}{[SO_2][NO_2]}$

Explanation:

The general equilibrium expression looks like this:

$K_{eq} = \frac{[C]^c[D]^d}{[A]^a[B]^b}$

In this expression,

-----> K = equilibrium constant

-----> uppercase letters = formulas

-----> lowercase letters = balanced equation coefficients

The products are in the numerator and the reactants are in the denominator. Since all of the molecules are gases, they should all be included in the expression. Since the coefficients in the balanced equation are all 1, they do not need to be represented in the expression.

The equilibrium constant expression is:

$K_{eq} = \frac{[SO_3][NO]}{[SO_2][NO_2]}$

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Suppose that a dependent quantity increases when the independent quantity is decreased. This kind of proportional relationship b

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Quinine, an antimalarial drug, is 8.63% nitrogen. There are two nitrogen atoms per molecule. What is the molecular weight of qui

Furkat [3]

Answer:

324.18 g/mol

Explanation:

Let the molecular mass of the antimalarial drug, Quinine is x g/mol

According to question,

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Also, according to the question,

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4 years ago

Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. express the nu

bagirrra123 [75]

<span>To calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. We will simply inspect the "number" of aluminum, sulfur, and oxygen atoms available per one mole of the compound. Here we have Al2(SO4)3, which means that for every mole of aluminum sulfate, there are 2 moles of aluminum, 3 (1 times 3) moles of sulfur, and 12 (4x3) moles of oxygen. Since we have four moles of Al2(SO4)3 given, we simply multiply 4 times the moles present per 1 mole of the compound. So we have 4x2 = 8 moles of Al, 4x3 = 12 moles of sulfur, and 4x12 = 48 moles of oxygen.

So the answer is:
8,12,48

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3 years ago

Read 2 more answers

A silicon wafer with dimensions 15.00 cm x 15.00 cm x 0.0400 cm

Oxana [17]

The silicon wafer contains 20.96 g of silicon.

The mole of a substance is related to its mass and molar mass by the following equation:

<h3>Mole = mass / molar mass ....... (1)</h3>

Making mass the subject of the above equation, we have

<h3>Mass = mole × molar mass ..... (2)</h3>

With the above formula (i.e equation 2), we can obtain the mass of silicon in the wafer as follow:

Mole silicon = 0.746 mole

Molar mass of silicon = 28.09 g/mol

<h3>Mass of silicon =? </h3>

Mass = mole × molar mass

Mass = 0.746 × 28.09

<h3>Mass of silicon = 20.96 g</h3>

Therefore, the mass of silicon in the wafer is 20.96 g

Learn more: brainly.com/question/24639749

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