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Lyrx [107]
3 years ago
14

5. At what phase of mitosis does the number of chromosomes double?

Chemistry
1 answer:
klasskru [66]3 years ago
5 0
This doesn't happen in mitosis. Mitosis is preceded by interphase. Interphase has three phases: G1, S and G2. What you call chromosome doubling happens in S phase.
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Use a periodic table to complete the table below:
Aleksandr [31]

Answer:

proton number of hydrogen :1

proton number of calcium : 20

number of electrons for fluorine : 9

number of electrons for iodine : 53

number of neutron hydrogen :0

number of neutron iodine : 74

number of neutron gold(Aurum) :118

Explanation:

to get the number of neutron by number of nukleon minus the number of proton..

gold is aurum

the number of nukleon u can get at the periodic table .. by looking at the biggest number.. thats all.. i hope u understanding my explanation :'D hhihi see ya

6 0
3 years ago
Calculate the pOH for a solutions with a pH of 12.34. Is the solution acidic or basic?
alexgriva [62]

Answer:

1.66 basic

Explanation:

4 0
3 years ago
Can anyone help me with any of the questions
Dafna11 [192]
Use the chart to help you look carefully at the numbers and the volumes to figure the questions out hope this helps
7 0
3 years ago
Which electrolyte is stronger, NaOH or Ca(OH)2? Why?
nataly862011 [7]

Answer:

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Explanation:

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8 0
3 years ago
Which of the following statements is true? A) This reaction will be spontaneous only at high temperatures. B) This reaction will
viktelen [127]

Answer:

D) This reaction will be nonspontaneous only at high temperatures.

Explanation:

According the equation of Gibb's free energy -

∆G = ∆H -T∆S

∆G = is the change in gibb's free energy

∆H = is the change in enthalpy

T = temperature

∆S = is the change in entropy .

And , the sign of the  ΔG , determines whether the reaction is Spontaneous or non Spontaneous or at equilibrium ,

i.e. ,

if

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  • ΔG > 0 , the reaction is non Spontaneous
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The reaction has the value for ∆H = negative , and ∆S = negative ,

Now ,

∆G = ∆H -T∆S

     = ( - ∆H ) - T( - ∆S )

     =  ( - ∆H ) +T(  ∆S )

Now, for making the reaction Spontaneous ΔG = negative ,

Hence ,

The temperature is low, then the value for  ΔG will be negative , i.e. , Spontaneous reaction .

And , vice versa , at higher temperature , the reaction will have ΔG positive , and the reaction will be non -Spontaneous reaction .

The standard free energy of formation will be zero , only for the compounds that are in their pure form ,

Hence , Al(s) will have ΔG = 0 .

7 0
3 years ago
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