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3 years ago

What gets oxidized in a galvanic cell made with magnesium and zinc electrodes?

Chemistry

2 answers:

Vlada [557]3 years ago

5 0

Answer:

mg(s)

Explanation:

ankoles [38]3 years ago

4 0

Answer: Magnesium

Explanation:

Galvanic cell is a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.

The standard reduction potential for magnesium and zinc are as follows:

$E^0_{[Mg^{2+}/Mg]}= -2.37V$

$E^0_{[Zn^{2+}/Zn]}=-0.76V$

Reduction takes place easily if the standard reduction potential is higher (positive) and oxidation takes place easily if the standard reduction potential is less (more negative).

Here Mg undergoes oxidation by loss of electrons, thus act as anode. Zinc undergoes reduction by gain of electrons and thus act as cathode.

$Mg\rightarrow Mg^{2+}+2e^-$

$Zn^{2+}+2e^-\rightarrow Zn$

Thus magnesium gets oxidized.

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3 years ago

Which best explains why water is able to “stick” to the side of glass?

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4 years ago

Read 2 more answers

In the bromination of arenes, which of the following statements regarding the reaction is true?a.The hydrocarbon is used in exce

Olenka [21]

The hydrocarbon is used in excess.

<h3><u>Explanation</u>:</h3>

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4 years ago

When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea

Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

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