Answer:
7.22 L
Explanation:
From the question,
Applying Charles law,
V₁/T₁ = V₂/T₂...................... Equation 1
Where V₁ = Initial volume of gas, V₂ = Final volume of gas, T₁ = Initial Temperature of gas in Kelvin, T₂ = Final Temperature of gas in Kelvin
Make V₂ the subject of the equation
V₂ = (V₁×T₂)/T₁................. Equation 2
Given: V₁ = 5.00 L, T₁ = 20 °C = (20+273) K = 293 K, T₂ = 150 °C = (150+273) K = 423 K
Substitute these value into equation 2
V₂ = (5.00×423)/293
V₂ = 7.22 L
Answer:
A. the bond's yield to maturity is equal to its coupon rate.
Explanation:
The coupon rate is that amount of bond measured on the loan amount whereas the maturity yield is the rate held up to the settlement date and the investment arise up to the maturity date.
Since the bond is currently trading at its face value that means the bond price is equal to the face or par value
So, the appropriate option is A.
Answer:
B.)
Explanation:
Gains PE and loses ke
and I'm sweet poison
please subscribe my channel
Answer:
Kc → 5.58×10⁻⁴
Explanation:
Equilibrium reaction is:
2NOCl (g) ⇄ 2NO (g) + Cl₂(g)
Initially we have 1.25 moles of NOCl
After the equilibrium, we have 1.10 moles. So, during the process:
(1.25 mol - 1.1 mol) = 0.15 moles have reacted.
As ratio are 2:2, and 2:1, 0.15 moles of NO and (0.15 /2) = 0.075 moles of chlorine, were produced in the equilibrium.
Finally in equilibrium we have: 1.10 moles of NOCl, 0.15 moles of NO and 0.075 moles of Cl₂. But these amount are not molar, so we need molar concentration in order to determine Kc:
1.10 mol /2.50L = 0.44 M
0.15 mol / /2.50L = 0.06 M
0.075 mol /2.50L = 0.03 M
Let's make expression for Kc → [Cl₂] . [NO]² / [NOCl]²
Kc = (0.03 . 0.06²) / 0.44² → 5.58×10⁻⁴
At chemical equilibrium, the rates<span> of the forward </span>reaction<span> and reverse </span>reactions<span> are: 18.2. a. equal to 0. c. at a ... </span>Spontaneous reactions<span>: 18.4. a. are </span>always exothermic<span>. b. </span>always take place<span> at a </span>rapid rate<span>. </span>