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Tasya [4]
3 years ago
5

How do I convert/scale a recipe using a t chart

Chemistry
1 answer:
Rina8888 [55]3 years ago
6 0

Answer:

Obtain the conversion factor by dividing the required yield (from Step 2) by the old yield (from Step 1). That is, conversion factor = (required yield)/(recipe yield) or conversion factor = what you NEED ÷ what you HAVE.

Explanation:

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If 5.100 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temp
emmasim [6.3K]
  <span>C6H12 = 6x12 + 6x1 = 78. 
The equation indicates that 2x78 = 156g benzene will produce 6542kJ. 
Using proportions you can then calculate that 
x/6542kJ = 7.9g / 156g 
x = 331.3kJ = 331300J. 

heat = mass x ΔT x 4.18J/g° 
ΔT = 331300J / (5691g x 4.18J/g°) = 13.9° 

final temp = 21 + 14° = 35°C</span>
4 0
3 years ago
Write one paragraph to explain what circuler motion is?
ZanzabumX [31]

Answer:

When a body moves in a circle with constant speed , it is said to be in uniform circular motion .

Explanation:

  • When an object moves in a circular path , its direction changes at each point .
  • This change in direction result in change of velocity (velocity is vector quantity which changes if direction of the object change) .However speed do not change (it is scalar quantity , not affected by Direction)
  • The Change in velocity produce acceleration ( a = v - u)
  • Hence The object always produce acceleration in uniform circular motion .So, Some force (centripetal force) is needed to keep the object in circular motion.
4 0
3 years ago
Who uses chemicals ?
nordsb [41]
Is there answer choices ??
4 0
3 years ago
Read 2 more answers
Si2C19<br> What is this compound
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Answer:

BROMOTRIPHENYLSILANE

Explanation:

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7 0
3 years ago
2. Calculate the atomic mass of an element that has two isotopes, each with 50.00% abundance. One isotope has a mass of 63.00 am
melamori03 [73]

Answer:

The atomic mass of element is 65.5 amu.

Explanation:

Given data:

Abundance of X-63 = 50.000%

Atomic mass of  X-63 = 63.00 amu

Atomic mass of X-68 = 68.00 amu

Atomic mass of element = ?

Solution:

Abundance of X-68 = 100-50 = 50%

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (50×63)+(50×68) /100

Average atomic mass =  3150 + 3400 / 100

Average atomic mass  = 6550 / 100

Average atomic mass = 65.5 amu.

The atomic mass of element is 65.5 amu.

7 0
3 years ago
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