Given a triangle ABC at points A = (-6, 3) B=(-4,7) C = (-2, 3), and a first transformation of up 2 and right
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Given :
An airplane flying at an altitude of 2600 m is approaching an airport run away located 56 km away.
To Find :
The airplane’s angle of decent.
Solution :
Height of plane, h = 2600 m.
Horizontal distance of airplane from vertices is, d = 56 km = 56000 m.
Let, angle of depression is Ф.
So,
Therefore, the angle of decent is 87.34°.
Hence, this is the required solution.