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poizon [28]
2 years ago
10

2.5 moles of a gas is enclosed in a 87.2 L cylinder with a moveable piston at 425 K and 1.0 atm. An additional 2.5 moles of gas

is added to the system and it is cooled to 273 K. The cylinder changes volume to maintain the pressure. What is the volume in the final system?

Chemistry
1 answer:
Nesterboy [21]2 years ago
4 0

Answer:

112 L

Explanation:

Since the pressure is being held constant, you can use the following variation of the Ideal Gas Law to find the new volume:

\frac{V_1}{T_1N_1}=\frac{V_2}{T_2N_2}

In this equation, "V₁", "T₁", and "N₁" represent the initial volume, temperature, and moles. "V₂", "T₂", and "N₂" represent the final volume, temperature, and moles.

V₁ = 87.2 L                             V₂ = ? L

T₁ = 425 K                              T₂ = 273 K

N₁ = 2.5 moles                       N₂ = 2.5 + 2.5 = 5.0 moles

\frac{V_1}{T_1N_1}=\frac{V_2}{T_2N_2}                                                   <----- Formula

\frac{87.2 L}{(425K)(2.5 moles)}=\frac{V_2}{(273 K)(5.0 moles)}                    <----- Insert values

\frac{87.2 L}{1062.5}=\frac{V_2}{1365}                                                    <----- Simplify denominators

0.08207=\frac{V_2}{1365}                                                 <----- Simplify left side

112L={V_2}                                                        <----- Multiply both sides by 1365

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How many moles of the Htion in 395 mL of 1.325 M sulfuric acid (H2SO4).
Irina18 [472]

Answer:

1.05 mol

Explanation:

Step 1: Given data

  • Molarity of sulfuric acid (M): 1.325 M (1.325 mol/L)
  • Volume of solution (V): 395 mL (0.395 L)

Step 2: Calculate the moles of sulfuric acid (n)

We will use the following expression.

M = n/V

n = M × V

n = 1.325 mol/L × 0.395 L = 0.523 mol

Step 3: Calculate the moles of H⁺

H₂SO₄ dissociates completely according to the following equation.

H₂SO₄ ⇒ 2 H⁺ + SO₄²⁻

The molar ratio of H₂SO₄ to H⁺ is 1:2. The moles of H⁺ are 2/1 × 0.523 mol = 1.05 mol.

7 0
3 years ago
What was the significance of Thompson’s Plum Pudding model of the atom?
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3 years ago
How many molecules are in 643.21 grams of Mg3(PO4)2?
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Answer:

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4 0
3 years ago
The heat of fusion of lead is 23.1 J/g. How much heat is absorbed as 85.0 g melt at<br> 328°C?
sp2606 [1]

Answer:

Q = 1964 J

Explanation:

Data Given:

latent heat of fusion for Lead (Lf)= 23.1 J/g

amount of ice (mass) = 85.0 gram

heat required to melt lead (Q) =?

Solution:

Latent heat of fusion: the amount of heat that required to melt certain amount of a substance. The total heat absorbed by substance is proportional to the total heat of fusion of the material.

Formula Used

             Q = mLf

Q = heat required to melt a substance

m = mass of the substance

Lf =latent heat of fusion

put values in above formula

             Q = mLf

             Q = 85 g x 23.1 J/g

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8 0
3 years ago
Calculate the electrical energy per gram of anode material for the following reaction at 298 K:
antiseptic1488 [7]

The answer is:

E per gram = 0.45 V

The explanation:

when MnO2 is the substance who oxidized here so, the oxidizing agent and the anode here is Li.

and when the molar mass of Li is = 7 g/mol

and in our reaction equation we have 1 mole of Li will give 3.15 V of the electrical energy

that means that :

7 g of Li gives → 3.15 V

So 1 g of Li will give→ ???

∴ The E per gram = 3.15 V / 7 g of Li

= 0.45 V

6 0
3 years ago
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