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2 years ago

7 − (6 ÷ 2)² + 2 jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

Mathematics

2 answers:

Vlada [557]2 years ago

8 0

Answer:

Step-by-step explanation:

7-(6/2)^2+2 = 4

pemdas

Parenthasis : 7 - (3) ^2 +2

Exponents : 7- 9 + 2

Multiplication : x

Division : x

Addition : 7-11

Subtraction : 4

Bess [88]2 years ago

7 0

Answer: 0

Step-by-step explanation: $\displaystyle\bf 7-(6\div2)^2+2=0 \\\\1)\ 6:2=3 \\\\2)\ 3^2=9 \\\\3)\ 7-9=-2 \\\\4) \ -2+2=0$

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Which of the following transforms y = x' to the graph of y = (x + 5)22

Anni [7]

Answer: A translation 5 units to the left... brainliest?

Step-by-step explanation: edge 2020

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2 years ago

arlik [135]

Given:

In a right angle triangle θ is an acute angle and $\tan\theta =\dfrac{3}{5}$ .

To find:

The value of $\cos \theta$ .

Solution:

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

We have,

$\tan\theta =\dfrac{3}{5}$

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

$Hypotenuse=\sqrt{Perpendicular^2+base^2}$

$Hypotenuse=\sqrt{(3x)^2+(5x)^2}$

$Hypotenuse=\sqrt{9x^2+25x^2}$

$Hypotenuse=\sqrt{34x^2}$

$Hypotenuse=x\sqrt{34}$

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos \theta=\dfrac{5x}{x\sqrt{34}}$

$\cos \theta=\dfrac{5}{\sqrt{34}}$

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Verizon [17]

$\dfrac{64}{9}=7\dfrac{1}{9}$

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3 years ago