Answer:
The probability is 0.3576
Step-by-step explanation:
The probability for the ball to fall into the green ball in one roll is 2/1919+2 = 2/40 = 1/20. The probability for the ball to roll into other color is, therefore, 19/20.
For 25 rolls, the probability for the ball to never fall into the green color is obteined by powering 19/20 25 times, hence it is 19/20^25 = 0.2773
To obtain the probability of the ball to fall once into the green color, we need to multiply 1/20 by 19/20 powered 24 times, and then multiply by 25 (this corresponds on the total possible positions for the green roll). The result is 1/20* (19/20)^24 *25 = 0.3649
The exercise is asking us the probability for the ball to fall into the green color at least twice. We can calculate it by substracting from 1 the probability of the complementary event: the event in which the ball falls only once or 0 times. That probability is obtained from summing the disjoint events: the probability for the ball falling once and the probability of the ball never falling. We alredy computed those probabilities.
As a result. The probability that the ball falls into the green slot at least twice is 1- 0.2773-0.3629 = 0.3576
Answer:
x^2-2x+1
Step-by-step explanation:
We can solve this by using FOIL
First, Outside, Inside, Last
Multiply the x with the x to get x^2
Then x times -1 for the outside numbers to get -x
Then -1 times x for the inside numbers to get -x
And finally -1 and -1 for the last numbers to get 1
Add the two -x to get -2x.
Put it all together
x^2-2x+1
43 not 100% shure good luck
Answer:
f(2)=1/3
Step-by-step explanation:
x=3
f(sqrt(3+1))=1/3
f(sqrt(4))=1/3
f(2)=1/3