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Veseljchak [2.6K]
2 years ago
7

What do you understand by the statement"the relative velocity of a body A with respect to body B".​

Engineering
1 answer:
Gre4nikov [31]2 years ago
5 0

The relative velocity is defined as the velocity of an object with respect to another observer. It is the time rate of change of relative position of one object with respect to another object.

<h3>What is the relative velocity of A with respect to B?</h3>

The relative velocity of A with respect to B= velocity of the body A – velocity of the body B.

<h3>What is relative velocity and its formula?</h3>

The relative velocity formula is expressed as. V → = V A B → + V B C → Where. VAB is the velocity with respect to A and B, VBC is the velocity with respect to B and C and VAC is the velocity with respect to A and C.

To learn more about relative velocity, refer

brainly.com/question/17228388

#SPJ9

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(Architecture) Sarah is an environmental activist. She frequently conducts various programs and activities in her community to p
ddd [48]

The council from which Sarah can obtain her building certification is;

<u><em>US Green Building Council</em></u>

  • We are told that Sarah is an environmental activist because she conducts a lot of programs to advocate for clean and sustainable environment.

Now, there is a program called LEED which is an acronym for <em>Leadership in </em>

<em>Energy and Environmental Design</em> standards that is necessary for those

that want to measure the greenness of buildings.

     This <em>LEED</em> program explained above is organized by an organization in

the United States of America (USA) known as US Green Building Council

(USGBC). This program is for everyone who wants to be a certified

environmental activist and thus i t is recommended that Sarah gets her

certification here.

Read more at; brainly.com/question/24611198

5 0
3 years ago
What is the governing ratio for thin walled cylinders?
Ann [662]

Answer:

The governing ratio for thin walled cylinders is 10 if you use the radius. So if you divide the cylinder´s radius by its thickness and your result is more than 10, then you can use the thin walled cylinder stress formulas, in other words:

  • if \frac{radius}{thickness} >10 then you have a thin walled cylinder

or using the diameter:

  • if \frac{diameter}{thickness} >20 then you have a thin walled cylinder
3 0
3 years ago
Explain 3 types of lubrication occurs in bearings?
Angelina_Jolie [31]

Answer:

The three types of lubrication occurred in the bearing are:

When the lubrication occur in the bearing it play an important role in the rolling life of bearing element. Basically, lubricant task is to reduced the friction.

1) Grease lubricant: Grease contain various type of additives which help in enhance the performance. It consist of oil where thickness are added as, this thickness improved the characteristics of grease.

2) Oil lubricant: This is used to reduced or minimized the friction and the lubricant oil is used to in those vehicles when they are motorized. Bearing lubricant oil is used to higher the speed capability.

3) Solid films: These are non fluid coating surface that are applied in the friction surface for prevention. It is used in very extreme situation where oil and grease types of lubricant does not work.  

8 0
3 years ago
Underground water is to be pumped by a 78% efficient 5- kW submerged pump to a pool whose free surface is 30 m above the undergr
maksim [4K]

Answer:

a) The maximum flowrate of the pump is approximately 13,305.22 cm³/s

b) The pressure difference across the pump is approximately 293.118 kPa

Explanation:

The efficiency of the pump = 78%

The power of the pump = 5 -kW

The height of the pool above the underground water, h = 30 m

The diameter of the pipe on the intake side = 7 cm

The diameter of the pipe on the discharge side = 5 cm

a) The maximum flowrate of the pump is given as follows;

P = \dfrac{Q \cdot \rho \cdot g\cdot h}{\eta_t}

Where;

P = The power of the pump

Q = The flowrate of the pump

ρ = The density of the fluid = 997 kg/m³

h = The head of the pump = 30 m

g = The acceleration due to gravity ≈ 9.8 m/s²

\eta_t = The efficiency of the pump = 78%

\therefore Q_{max} = \dfrac{P \cdot \eta_t}{\rho \cdot g\cdot h}

Q_{max} = 5,000 × 0.78/(997 × 9.8 × 30) ≈ 0.0133 m³/s

The maximum flowrate of the pump Q_{max} ≈ 0.013305 m³/s = 13,305.22 cm³/s

b) The pressure difference across the pump, ΔP = ρ·g·h

∴ ΔP = 997 kg/m³ × 9.8 m/s² × 30 m = 293.118 kPa

The pressure difference across the pump, ΔP ≈ 293.118 kPa

6 0
3 years ago
If an imbalance occurs, the _
pochemuha

A. AFGI is the answer for this question.

7 0
3 years ago
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