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eduard
3 years ago
12

During an expansion process, the pressure of a gas changes from 15 to 140 psia according to the relation P = aV + b, where a = 5

psia/ft3 and b is a constant. If the initial volume of the gas is 7 ft3, calculate the work done during the process.
Engineering
1 answer:
Dominik [7]3 years ago
5 0

The work done during the process is 359 btu

<u></u>

<u>Explanation:</u>

Given-

P1 = 15psia

P2 = 140 psia

V1 = 7ft³

a = 5 psia/ft³

b = C

P = aV +b

Work done, W = ?

P1 = aV1 + b

15 = 5 (7) + b

b = -20 psia

P2 = aV2 + b

140 = 5 ( V2) - 20

V2 = 32 ft³

The work done by the process is the area under the curve which is trapezoidal.

Therefore,

Work done, W = area of trapezoid

= (P2 + P1 / 2) (V2 - V1)

= ( 140 + 15 / 2 ) ( 32 - 7)

= 1937.5 psia ft³

= 1937.5/ 5.4039 = 359 btu

Therefore, the work done during the process is 359 btu

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Attached is the solution to the above question.

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3 years ago
An inventor claims to have developed a food freezer that at steady state requires a power input of 0.25 kW to extract energy by
Serga [27]

Answer:

investor claim is acceptable

Explanation:

given data

Win = 0.25 kW

Qc = 3000 J/s = 3kW

Th = 293 K

Tc = 270 K

solution

we get here coefficient of performance of cycle is

coefficient of performance = \frac{Qc}{Win}    ..................1

put here value and we get

coefficient of performance = \frac{3}{0.25}  

coefficient of performance = 1.2

and

coefficient of performance of ideal refrigeration is

coefficient of performance = \frac{Tc}{Th-Tc}    ..................2

coefficient of performance = \frac{270}{293-270}  

coefficient of performance = 11.74

and

we can see here that coefficient of performance of ideal refrigeration  is is more than real cycle coefficient of performance

so investor claim is acceptable

6 0
2 years ago
Que es el crecimiento?
Grace [21]

Answer:

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Explanation:

4 0
2 years ago
Read 2 more answers
Determine the resistance of 3km of copper having a diameter of 0,65mm if the resistivity of copper is 1,7x10^8
LUCKY_DIMON [66]

Answer:

Resistance of copper = 1.54 * 10^18 Ohms

Explanation:

<u>Given the following data;</u>

Length of copper, L = 3 kilometers to meters = 3 * 1000 = 3000 m

Resistivity, P = 1.7 * 10^8 Ωm

Diameter = 0.65 millimeters to meters = 0.65/1000 = 0.00065 m

Radius, r = \frac {diameter}{2}

Radius = \frac {0.00065}{2}

Radius = 0.000325 m

To find the resistance;

Mathematically, resistance is given by the formula;

Resistance = P \frac {L}{A}

Where;

  • P is the resistivity of the material.
  • L is the length of the material.
  • A is the cross-sectional area of the material.

First of all, we would find the cross-sectional area of copper.

Area of circle = πr²

Substituting into the equation, we have;

Area  = 3.142 * (0.000325)²

Area = 3.142 * 1.05625 × 10^-7

Area = 3.32 × 10^-7 m²

Now, to find the resistance of copper;

Resistance = 1.7 * 10^{8} \frac {3000}{3.32 * 10^{-7}}

Resistance = 1.7 * 10^{8} * 903614.46

<em>Resistance = 1.54 * 10^18 Ohms </em>

3 0
3 years ago
An industrial system is rated at 600 v the system includes a partially exposed terminal block thats mounted on a bulkhead a new
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Answer:

10 ft or 3.048 m (for unqualified person)

1.09 ft or 0.33 m (for qualified person)

Explanation:

OSHA has prescribed "Minimum Approach Distance - MAD" to ensure safety of personnel working with electrical power lines.

For a unqualified person:

The minimum approach distance is 10 ft or 3.048 m

For a qualified person:

For a voltage in the range of 300V to 750V (Phase to Ground or Phase to Phase) the minimum approach distance is 1.09 ft or 0.33 m

Since 600V lies in the above range hence it is applicable on 600V.

OSHA has developed a full list of minimum approach distance according to the level of voltages (50V to 72000V)

7 0
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