All categories

3 years ago

7.489 ÷ 0.09. Explain.

Mathematics

2 answers:

liq [111]3 years ago

8 0

it is 83.21111111 ..............................

Kisachek [45]3 years ago

6 0

83.2111111111.

0.09 fits into 7.498, 83.2111111111

You might be interested in

I really need help????<br> Plz answer quickly

Julli [10]

Answer:

3 7 8 2 6 4 1 10 3 5 9 the answer

6 0

3 years ago

Which ten thousand does 117,290 round to

Leni [432]

Answer:

120,000

Step-by-step explanation:

because seven in greater than 5 so it would round up

3 0

3 years ago

Two lines are intersected by a third line. If 2 6, which must be true about 2? 2 5 2 is complementary to 5. m2 = m8 2 is supplem

sineoko [7]

If this scenario is a pair of parallel lines intersected by a transversal then it is true that
2 = 6
Then, among the choices, the statement that is true is
2 is supplementary to 8 since 6 is supplementary to 8
By transitivity property, 2 is supplementary 8

4 0

3 years ago

Read 2 more answers

Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen

Jobisdone [24]

Parameterize $S$ by the vector function

$\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k$

so that the normal vector to $S$ is given by

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}$

In this case, the normal vector is

$\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k$

with magnitude $\sqrt{1^2+2^2+1^2}=\sqrt6$ . The integral of $f(x,y,z)=e^z$ over $S$ is then

$\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx$

where $T$ is the region in the $x,y$ plane over which $S$ is defined. In this case, it's the triangle in the plane $z=0$ which we can capture with $0\le x\le8$ and $0\le y\le\frac{8-x}2$ , so that we have

$\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}$

5 0

3 years ago

Write a statement relating the opposites of each of the given numbers.

Leokris [45]

Yes -1/5 is less than 1/3

8 0

3 years ago

Read 2 more answers