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2 years ago

(x-1)/2=2 please help

Mathematics

2 answers:

Lilit [14]2 years ago

7 0

Answer:

x = 5

Step-by-step explanation:

5 - 1 = 4

4/2 =2

Hope this helps!

elena-s [515]2 years ago

7 0

Answer:

Solution

= 5

x-1/2=2

x-1/2=2X2

x-1=4

x-1+1=4+1

Add the numbers x=5

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At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st

EastWind [94]

<u>Answer:</u>

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

<u>Step-by-step explanation:</u>

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = $\frac{609}{58} = 10.5$

Checking for ratios of the given options:

A. $\frac{483}{42} =11.5$

B. $\frac{378}{28} =13.5$

C. $\frac{504}{48} =10.5$

D. $\frac{560}{56} =10$

E. $\frac{315}{30} =10.5$

Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.

7 0

2 years ago

Read 2 more answers

The time taken to assemble a laptop computer in a certain plant is a random variable having a normal distribution of 20 hours an

ludmilkaskok [199]

Answer:

a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.

b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

$\mu = 20, \sigma = 2$