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3 years ago

Help Please Mathhh!!!!!!!!!!!!!!!

Mathematics

2 answers:

irga5000 [103]3 years ago

8 0

Answer: the Nswer for this is 30 people

Step-by-step explanation:

Misha Larkins [42]3 years ago

4 0

Answer:

10n=40 n=4

Step-by-step explanation:

10n=40 divide each side by 10

n=40/10 simplify

n=4

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How to convert base two to base three

sladkih [1.3K]

Consider this example: say we want to convert x = 11 0101 1001₂ to base 3.

The binary expansion of x is

x = 1×2⁹ + 1×2⁸ + 1×2⁶ + 1×2⁴ + 1×2³ + 1×2⁰

which in base 10 reduces to

x = 512 + 256 + 64 + 16 + 8 + 1 = 857

Recall the first several powers of 3:

3⁰ = 1; 3¹ = 3; 3² = 9; 3³ = 27; 3⁴ = 81; 3⁵ = 243; 3⁶ = 729

Now it's a matter of computing quotients and remainders. Pick the largest power of 3 that fits into the target number, then check the remainder and repeat.

• How many times does the 729 go into 857? 1 time, and it leaves a remainder of 128, or

857 = 1×729 + 128 = 1×3⁶ + 128

• How many times does 81 go into 128? Also 1 time, so

128 = 1×81 + 47 = 1×3⁴ + 47

• How many times does 27 go into 47? Also 1 time,

47 = 1×27 + 20 = 1×3³ + 20

• How many times does 9 go into 20? 2 times,

20 = 18 + 2 = 2×9 + 2 = 2×3² + 2

• How many times does 1 go into 2? Also 2 times,

2 = 2 + 1 = 2×1 + 0 = 2×3⁰

So we found

857 = 1×3⁶ + 1×3⁴ + 1×3³ + 2×3² + 2×3⁰

which is the ternary expansion of x,

x = 1 011 202₃

6 0

3 years ago

Which choice below is a common multiple of 8 and 10 (but not the least common multiple).

Ilya [14]

Answer:

160

Step-by-step explanation:

4 is too low, 90 cant be divided by 8 and 160 is the only answer even though it is highest number

8 0

3 years ago

Read 2 more answers

Solve de system by elimination. x-5y=3 4x-4y=12

Anit [1.1K]

If we multiply the top equation by -4 we can get rid of the x so:

-4x+20y=-12

4x-4y=12

Add these up

16y=0

Y=0

X=3

7 0

3 years ago

TRIGONOMETERY REVIEW PLEASE HELP DUE TOMMOROW

Alisiya [41]

I’m pretty sure this is how you do these kinds of questions, but I may be entirely wrong, so don’t 100% trust me on this one

6 0

3 years ago

In a murder investigation, the temperature of a corpse was 32.5 degrees C at 1:30 pm and 30.3 degrees C an hour later. Normal bo

svp [43]

Let $T(t)$ be the temperature of the body $t$ hours after 1:30 PM. Then $T(0) = 32.5$ and $T(1) = 30.3$ .

Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T-20)$ . Now let $y = T - 20$ , so
$y(0) = T(0) - 20 = 32.5 - 20 = 12.5$ , so $y$ is a solution to the initial value problem $dy/dt = ky$ with $y(0) = 12.5$ .
By separating and integrating, we have $y(t) = y(0)e^{kt} = 12.5e^{kt}$ .

$y(1) = 30.3 - 20\ \Rightarrow\ 12.5e^{k(1)} = e^{k} = \frac{10.3}{12.5}\ \Rightarrow \\
k = \ln \frac{10.3}{12.5}
$

$y(t) = 37 - 20\ \Rightarrow\ 12.5e^{kt} = 17\ \Rightarrow\ e^{kt} = \frac{10.3}{12.5} \ \Rightarrow \\ \\
kt = \ln \frac{10.3}{12.5}\ \Rightarrow\ t = \left( \ln \frac{17}{12.5} \right)/ \frac{10.3}{12.5} \approx -1.588 \mathrm{\ h}$

≈ 95 minutes. Thus the murder took place about 95 minutes before 1:30 PM, or 11:55 AM.

6 0

3 years ago