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2 years ago

Help Please Mathhh!!!!!!!!!!!!!!!

Mathematics

2 answers:

irga5000 [103]2 years ago

8 0

Answer: the Nswer for this is 30 people

Step-by-step explanation:

Misha Larkins [42]2 years ago

4 0

Answer:

10n=40 n=4

Step-by-step explanation:

10n=40 divide each side by 10

n=40/10 simplify

n=4

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How do i do 56 1/4% it's a mixed fraction with a percent?

Pepsi [2]

Answer: 56 1/4 % = 52.25 % = 52.25 /100 = 0.5225
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4 0

2 years ago

Solve each compound inequality. Graph your solutions. 5 + m > 4 or 7m< -35

Yuliya22 [10]

Answer:

Solving the inequality $5 + m > 4\: or\: 7m< -35$ we get $\mathbf{m>-1\:or\: \:m$

The graph of the inequality is shown in figure attached.

Step-by-step explanation:

We need to Solve each compound inequality $5 + m > 4\: or\: 7m< -35$

Solving the inequalities

For solving compound inequalities we solve both inequalities simultaneously and find the value of m.

For solving 5+m > 4, we subtract 5 from both sides.

While solving 7m < -35, we divide both sides by 7 to get value of m

Applying these functions we get:

$5 + m > 4\: or\: 7m< -35\\m>4-5\:or\:m-1\:or\:m$

So, solving the inequality $5 + m > 4\: or\: 7m< -35$ we get $\mathbf{m>-1\:or\: \:m$

The graph of the inequality is shown in figure attached.

5 0

2 years ago

(x^2y+e^x)dx-x^2dy=0

klio [65]

It looks like the differential equation is

$\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0$

Check for exactness:

$\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x$

As is, the DE is not exact, so let's try to find an integrating factor µ(x, y) such that

$\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0$

*is* exact. If this modified DE is exact, then

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}$

We have

$\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu$

Notice that if we let µ(x, y) = µ(x) be independent of y, then ∂µ/∂y = 0 and we can solve for µ :

$x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}$

The modified DE,

$\left(e^{-x}y + \dfrac1{x^2}\right) \,\mathrm dx - e^{-x}\,\mathrm dy = 0$

is now exact:

$\dfrac{\partial\left(e^{-x}y+\frac1{x^2}\right)}{\partial y} = e^{-x} \\\\ \dfrac{\partial\left(-e^{-x}\right)}{\partial x} = e^{-x}$

So we look for a solution of the form F(x, y) = C. This solution is such that

$\dfrac{\partial F}{\partial x} = e^{-x}y + \dfrac1{x^2} \\\\ \dfrac{\partial F}{\partial y} = e^{-x}$

Integrate both sides of the first condition with respect to x :

$F(x,y) = -e^{-x}y - \dfrac1x + g(y)$

Differentiate both sides of this with respect to y :

$\dfrac{\partial F}{\partial y} = -e^{-x}+\dfrac{\mathrm dg}{\mathrm dy} = e^{-x} \\\\ \implies \dfrac{\mathrm dg}{\mathrm dy} = 0 \implies g(y) = C$

Then the general solution to the DE is

$F(x,y) = \boxed{-e^{-x}y-\dfrac1x = C}$

5 0

2 years ago

Heather has 2 less than 5 times the amount of shoes that Donna has. Gina has 1 more than 2 time

gogolik [260]

Answer:

a. (5x-2)-(2x+1)

b. 3x-3

c.39

Step-by-step explanation:

8 0

2 years ago

What is the answer to this in cm

jasenka [17]

The hardest part is finding the length of the curve at the top. To find arc length, multiply the circumference by the arc angle divided by full angle (360°) in a circle. Or:
$s = (2\pi r)( \frac{x}{360})$
x, the arc angle in a semicircle, is 180°.
r, the radius is 7/2 = 3.5.
Now just plug the numbers in and solve for arc length, s.

s = 2π(3.5)(1/2) ≈ 11.00

Now just add up all the sides. 11cm + 10cm + 10cm + 7cm = 38 cm.

5 0

2 years ago