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worty [1.4K]
1 year ago
15

The graph of the function f(x) = –(x + 1)2 is shown. Use the drop-down menus to describe the key aspects of the function. The ve

rtex is the . The function is positive . The function is decreasing . The domain of the function is . The range of the function is .
Mathematics
1 answer:
eimsori [14]1 year ago
8 0

The graph of the function f(x) = -(x+1)^2 shows that the domain of the function f(x) = -(x+1)² is: -∞ < x < ∞. The range of the function is f(x) ≤ 0.

<h3>What is the graph of a function?</h3>

The graph of a function is the arrangement of all ordered pairs of the function. Typically, they are expressed as points in a cartesian coordinate system. The graph of f is the collection of all ordered pairings (x, f(x)) such that x lies inside the domain of f.

The graph of a function might similarly be defined as the graph of the equation y = f(x). As a result, the graph of a function is a subset of the graph of an equation.

From the given information: the graph of the function f(x) = -(x+1)² can be determined if the domain, the range, and the vertex of the function are known.

  • The domain of the function f(x) = -(x+1)² is: -∞ < x < ∞
  • The range of the function is f(x) ≤ 0
  • The x-intercepts and the y-intercepts are (-1,0) and (0, -1) respectively
  • The vertex is maximum at (-1,0)

Since the parabola curve from the graph shows that the graph is facing down, then the function is negative and decreasing.

Learn more about the graph of a function here:

brainly.com/question/24696306

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What is the scale factor?​
kkurt [141]

35/42 =5/6

so the answer is 5/6.

6 0
2 years ago
Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

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6 0
2 years ago
if your front yard is 65ft by 45ft and your backyard is 35ft by 45ft. how much fencing should you buy
sveta [45]
If 45' is the width of the house, then the front yard would have 65+45+65 feet = 175 feet, and the back yard would have 35 + 45 + 35 = 115 feet.
the total would be 290 feet.


3 0
3 years ago
What is the reference angle for 192º?​
Aleonysh [2.5K]

Answer:

78º

Step-by-step explanation:

<u>Note</u> : -

In mathematics, the reference angle is defined as the acute angle and it is measuring less than 90 degrees. It is always the smallest angle, and it makes the terminal side of an angle with the

x - axis.

<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>1</u> : -

Find where 192º lies in which quadrant.

192º lies in 3rd quadrant ( between

180º and 270º )

<u>S</u><u>t</u><u>e</u><u>p</u><u> </u><u>2</u> : -

Subtract : 270 - 192

270 - 192 = 78º

( Since, 192º is greater than 180º, is subtracted from 270º )

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u> : -

78º is the reference angle for 192º.

3 0
2 years ago
X+2y=4<br> 2x-2y=5 <br> what is the answer
Tom [10]

x + 2y = 4

2x - 2y = 5

Adding both the equations:

x + 2y + 2x - 2y = 9

3x = 9

x = 3

y = 4-x /2 = 1/2

4 0
3 years ago
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