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Delicious77 [7]
3 years ago
13

Can you please help me on this it says fully simplify using only positive exponents 5x8y7/25x4y

Mathematics
1 answer:
dangina [55]3 years ago
4 0

Answer:

1/5x^12 * y^8.

Step-by-step explanation:

((5x^8*y^7/25)x^4)(y)

=1/5x^12 * y^8.

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6 0
2 years ago
How can you use 260 divided by 13 to help you find 286 divided by 13
Alexeev081 [22]

Answer:

Well, 260 divided by 13 is 20.

286-260=26

And 26 divided by 13 is 2.

Step-by-step explanation:

So there's that-

Brainliest??

4 0
3 years ago
Please help me with this problem​
ser-zykov [4K]

Answer:

d=−bc+a/0.5bc

Step-by-step explanation:

Let's solve for d.

a=0.5bcd+bc

Step 1: Flip the equation.

0.5bcd+bc=a

Step 2: Add -bc to both sides.

0.5bcd+bc+−bc=a+−bc

0.5bcd=−bc+a

Step 3: Divide both sides by 0.5bc.

0.5bcd/0.5bc = −bc+a/0.5bc

d=−bc+a/0.5bc

7 0
3 years ago
CSK won by 2 wickets last ball thriller​
KengaRu [80]

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6 0
3 years ago
Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De
Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is,\lambda=\frac{1}{\mu}=\frac{1}{7}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx

                      =\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0
3 years ago
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