Can you please help me on this it says fully simplify using only positive exponents 5x8y7/25x4y

If alpha and beta are zeroes of polynomial fx = 4x2-5x-1. Pls answer full questiob

Ede4ka [16]

<h3>...................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................</h3><h2>I like 15 yr old girls.</h2>

6 0

2 years ago

How can you use 260 divided by 13 to help you find 286 divided by 13

Alexeev081 [22]

Answer:

Well, 260 divided by 13 is 20.

286-260=26

And 26 divided by 13 is 2.

Step-by-step explanation:

So there's that-

Brainliest??

4 0

3 years ago

Please help me with this problem

ser-zykov [4K]

Answer:

d=−bc+a/0.5bc

Step-by-step explanation:

Let's solve for d.

a=0.5bcd+bc

Step 1: Flip the equation.

0.5bcd+bc=a

Step 2: Add -bc to both sides.

0.5bcd+bc+−bc=a+−bc

0.5bcd=−bc+a

Step 3: Divide both sides by 0.5bc.

0.5bcd/0.5bc = −bc+a/0.5bc

d=−bc+a/0.5bc

7 0

3 years ago

CSK won by 2 wickets last ball thriller

KengaRu [80]

Answer:

yes I see also csk CRICKET . CSK TEAM IS OP

6 0

3 years ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of <em>X</em> is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago