Answer:
CH₂O
Explanation:
From the question given above, the following data were obtained:
Carbon (C) = 39.9%
Hydrogen (H) = 6.7%
Oxygen (O) = 53.4%
Empirical formula =?
The empirical formula of acetic acid can be obtained as follow:
C = 39.9%
H = 6.7%
O = 53.4%
Divide by their molar mass
C = 39.9 / 12 = 3.3
H = 6.7 / 1 = 6.7
O = 53.4 / 16 = 3.3
Divide by the smallest
C = 3.3 / 3.3 = 1
H = 6.7 / 3.3 = 2
O = 3.3 / 3.3 = 1
The empirical formula => CH₂O
The final temperature :T₂=411.125 K = 138.125 °C
<h3>Further explanation</h3>
Given
T₁=-20 °C+273 = 253 K
V₁=40 ml
V₂=65 ml
Required
Final temperature
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
Input the value :
T₂=(V₂.T₁)/V₁
T₂=(65.253)/40
T₂=411.125 K = 138.125 °C
1.97moles
106.7/(1.01x2+16)/3x1 = 1.97
So what you do is you write out each element separately and how many of that element on either side of the arrow S-8|S-1
O-2|O-2
on one side theres 8 (S) and 2 (O) and 1(S) and 2(O) if you put a number in front to balance it you are multiplying it the elements number like
SO2 if I put a 2 in front now I will have 2(S) and 4(O)
Answer is 1,8,8
