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Iteru [2.4K]
3 years ago
5

How many moles of C2H5OH are needed to generate 106.7 g of H2O?

Chemistry
1 answer:
uysha [10]3 years ago
4 0
1.97moles

106.7/(1.01x2+16)/3x1 = 1.97
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Which of the following is not part of Dalton's atomic theory?
lakkis [162]
I think its A because some scientist from the Department of Physics of Northeastern University found out that is not a part of Dalton's atomic theory.
3 0
4 years ago
You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30
dimaraw [331]

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

3 0
3 years ago
A can contains a gas with a volume of 86 mL at 30oC. What is the volume in the can if it is heated to 65oC?
Ber [7]

Answer:

New volume of gas = 95.93 ml (Approx)

Explanation:

Given:

Old volume of gas = 86 ml

Old temperature = 30°C = 30 + 273 = 303 K

New temperature = 65°C = 65 + 273 = 338 K

Find:

New volume of gas

Computation:

V1T2 = V2T1

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New volume of gas = 95.93 ml (Approx)

8 0
3 years ago
Write some example of misicible and immisicible liquid​
Eduardwww [97]

Explanation:

miscible liquids: water and alcohol

immiscible liquids: water and oil

4 0
3 years ago
A canoe displaces 100 L of water. Water weighs 9.8 N/L. What is the buoyant force on the canoe?
Setler79 [48]

Hey there!


The Buoyant force is going to be equal to the weight of the water displaced and it would be like this 100 L(9.8 N/L) = 980 N.



Hope this helped and mind marking me brainliest. Thank you!

5 0
4 years ago
Read 2 more answers
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