The answer is 2) Its atomic number because that’s what the protons represent
Answer: two or more different pure substances, which may be elements or compounds.
Explanation:
The term varieties of matter is kind of ambiguos since it is not defined.
The best approach to the question is to think of matter as it can be classified into to kinds: pure substaces and mixtures.
Elements and compounds are pure substances.
Elements are pure substances constituted by only one kind of atoms. An element cannot be divided into simpler substances either by physical or chemical media.
A compound is a chemical combination of two or more different elements. A compound can be divided into simpler substances by chemical reactions, but not by physical media. The properties of compounds are different of those of the elements of which they are constituted. The composition of a compoind (ratio among its elements) is fixed.
A mixture is the physical combination of two or more pure substances (either different elements or compounds) which can be mixed in any proportion. This is, its composition is variable. The substances that form the mixture can be separated by physical media.
Answer:
The detailed calculation is shown in the attached file.
last condition (1000 K in 150.000 dm3) will have the least deviations and it is the condition where real gas will behave as ideal gases
Explanation:
Real gas behave more ideally or they tend towards ideality when there is the least deviation, or their inter-molecular forces between their molecules are mainly responsible for their deviations as such gases with the strongest intermolecular forces shows the strongest deviations. As such, when their is an increase in temperature and volume and a decrease in pressure, real gas tends towards ideal gas in this case.
From the three conditions given, it is obvious that the last condition(1000 K in 150.000 dm3) will have the least deviations.
Answer:
an ideal gas does not exist except as a conceptual notion, an ideal. Physicists and chemists idealized the behaviour of real gases so that they could explain these phenomena. Under conditions of low pressure and high temperature, all gases behave like real gases, even gases such as UF6 .
<u>Answer:</u> The mass of iron (II) oxide that must be used in the reaction is 30.37
<u>Explanation:</u>
The given chemical reaction follows:

By Stoichiometry of the reaction:
When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.
So, when 44.7 kJ of energy is released,
of iron (II) oxide is reacted.
Now, calculating the mass of iron (II) oxide by using the equation:

Moles of iron (II) oxide = 0.423 moles
Molar mass of iron (II) oxide = 71.8 g/mol
Putting values in above equation, we get:

Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37