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4 years ago

PLEASE HELP ASAPPPP

1 answer:

8 0

So what you do is you write out each element separately and how many of that element on either side of the arrow S-8|S-1
O-2|O-2
on one side theres 8 (S) and 2 (O) and 1(S) and 2(O) if you put a number in front to balance it you are multiplying it the elements number like
SO2 if I put a 2 in front now I will have 2(S) and 4(O)

Answer is 1,8,8

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Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).

To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.

For example, in this skeleton equation:

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Write the coefficient 2 in the products.

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3 years ago

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2 years ago

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Answer:

$CuCl_{2}(aq.)$ will form a precipitate of insoluble $CuCO_{3}$ when aqueous $Na_{2}CO_{3}$ is added.

Explanation:

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When $Na_{2}CO_{3}$ is added to given solutions, a double displacement reaction takes place in each solution to form a sodium salt and a carbonate salt.

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3 years ago