Let's solve your equation step-by-step.
2(3x−1)=−6x−2
Step 1: Simplify both sides of the equation.
2(3x−1)=−6x−2
(2)(3x)+(2)(−1)=−6x+−2(Distribute)
6x+−2=−6x+−2
6x−2=−6x−2
Step 2: Add 6x to both sides.
6x−2+6x=−6x−2+6x
12x−2=−2
Step 3: Add 2 to both sides.
12x−2+2=−2+2
12x=0
Step 4: Divide both sides by 12.
12x/12= 0/12
x=0
Answer:
x=0
HOPE THIS HELPS!!! :)
In a mechanical system, it is a law that energy should be conserved. In this case, what is the initial energy should be equal to the total energy after the motion happened. We do as follows:
PE(at rest) = KE(during motion) + PE(after motion)
51450 J = KE(during motion) + 32781 J
KE(during motion) = 18669 J
