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Ksenya-84 [330]

3 years ago

5

Select the correct answer from each drop-down menu. A quarter is approximately 0.07 inches thick. A dollar bill is approximately

4.3 × 10-3 inches thick. A is thicker than a by m × 10n inches, where m = and n = . Undo

1 answer:

vovangra [49]3 years ago

8 0

Answer:

m = 6.57 and n = -2

Step-by-step explanation:

To answer this question, one will have to covert the thickness of a dollar to standard notation and then compare the two values.

4.3 × 10-3 = 4.3/1000

= 0.0043

Now, compare

0.07 =compared to 0.0043

0.07- 0.0043

= 0.0657

0.0657 = 6.57 x 10^-2

A quarter is thicker than a dollar by 6.57 x 10^-2..... 1

m × 10n........ 2

Comparing 1 and 2

m = 6.57 and n = -2

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If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure & the perimeter of triangle ABC.

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Answer:

$Perimeter = 38.6$

Step-by-step explanation:

Given

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Required

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To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

$Perimeter = A B + B\ C + A\ C$

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

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Substitute values for BF and FC;

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Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

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$A\ B^2 = B\ F^2 + A\ F^2$

Substitute values for B F and A B;

$13^2 = 9^2 + A\ F^2$

$169= 81 + A\ F^2$

$A\ F^2 = 169 - 81$

$A\ F^2 = 88$

$A\ F = \sqrt{88$

$A\ F = 9.4$

Since F lies on line A C:

$A\ C = A\ F + F\ C$

$A\ C = 9.4 + 5.6$

$A\ C = 15.0$

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$Perimeter = 13 + 10.6 + 15.0$

$Perimeter = 38.6$

<em>Hence, the perimeter is 38.6</em>

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Step-by-step explanation:

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